在OpenGL中,如果我想画一个填充的圆形,我会这样做:
void DrawPoint(float X, float Y, float Z, float Radius) const
{
glRasterPos2f(X, Y);
glPointSize(Radius);
glBegin(GL_POINTS);
glVertex3f(X, Y, Z);
glEnd();
glPointSize(this->PointSize);
glFlush();
}
然而,我在Direct-X中找不到glPointSize
的等效物。因此,我尝试了以下内容:
struct Vector3
{
double X, Y, Z;
};
#include <vector>
void DrawCircle1(float X, float Y, DWORD Color)
{
const int sides = 20;
std::vector<D3DXVECTOR3> points;
for(int i = 0; i < sides; ++i)
{
double angle = D3DX_PI * 2 / sides * i;
points.emplace_back(D3DXVECTOR3(sin(angle), cos(angle), 0));
}
device->DrawPrimitiveUP(D3DPT_TRIANGLEFAN, sides, &points[0], sizeof(D3DXVECTOR3));
}
void DrawCircle2(float CenterX, float CenterY, float Radius, int Rotations)
{
std::vector<D3DXVECTOR3> Points;
float Theta = 2 * 3.1415926535897932384626433832795 / float(Rotations);
float Cos = cosf(Theta);
float Sine = sinf(Theta);
float X = Radius, Y = 0, Temp = 0;
for(int I = 0; I < Rotations; ++I)
{
Points.push_back(D3DXVECTOR3(X + CenterX, Y + CenterY, 0));
Temp = X;
X = Cos * X - Sine * Y;
Y = Sine * Temp + Cos * Y;
}
device->DrawPrimitiveUP(D3DPT_TRIANGLEFAN, Points.size(), &Points[0], sizeof(D3DXVECTOR3));
}
但是这些都不起作用。我无法弄清为什么什么都不起作用。第一个绘制了一个巨大的黑色圆圈,第二个绘制了一个长三角形。
有什么想法可以在Direct-X中绘制填充的圆或特定大小和颜色的点吗?