可以使用Python列表构建一个NumPy数组吗?
import numpy as np
a = np.array( [2,3,4] )
或者同样从嵌套列表中获取:
import numpy as np
a = np.array( [[2,3,4], [3,4,5]] )
你是指像这样吗?
from numpy import array
a = array( your_list )
import numpy as np
myList = [1, 2, 3]
np.array(myList).dump(open('array.npy', 'wb'))
...然后读取:
myArray = np.load(open('array.npy', 'rb'))
import numpy as np
# b is some list, then ...
a = np.array(b).reshape(lengthDim0, lengthDim1);
将给定的数组b按reshape指定的形状转换为数组a。
这里是一个更完整的例子:
import csv
import numpy as np
with open('filename','rb') as csvfile:
cdl = list( csv.reader(csvfile,delimiter='\t'))
print "Number of records = " + str(len(cdl))
#then later
npcdl = np.array(cdl)
也许:
import numpy as np
a=[[1,1],[2,2]]
b=np.asarray(a)
print(type(b))
输出:
<class 'numpy.ndarray'>
import numpy as np
... ## other code
一些列表推导式
t=[nodel[ nodenext[i][j] ] for j in idx]
#for each link, find the node lables
#t is the list of node labels
使用numpy库中指定的数组方法将列表转换为numpy数组。
t=np.array(t)
import numpy as np
,然后a = np.array([[2,3,4],[3,4,5]])
呢? - SDsolar