我有一个数据库,其中包含名为'crigsStaffActivity'的表。我成功地检索到了值并将其显示出来。但结果不符合我的期望。
创建带值的表的脚本
CREATE TABLE [dbo].[crigsStaffActivity]
(
[projectRef] [varchar](200) NOT NULL,
[activityLine] [int] NOT NULL,
[cost] [real] NOT NULL,
[staffCost] [varchar](500) NOT NULL
) ON [PRIMARY]
GO
INSERT [dbo].[crigsStaffActivity] ([projectRef], [activityLine], [cost], [staffCost])
VALUES (N'MRC/CRIGS/330', 1, 1, N'ProjectLeader'),
(N'MRC/CRIGS/330', 2, 2, N'Research Collaborators'),
(N'MRC/CRIGS/330', 1, 1, N'Project Collaborators'),
(N'MRC/CRIGS/330', 2, 2, N'Project Collaborators'),
(N'MRC/CRIGS/330', 2, 3, N'Research/Project Assistant');
ALTER TABLE [dbo].[crigsStaffActivity]
ADD CONSTRAINT [DF__crigsStaff__cost__5535A963] DEFAULT ((0)) FOR [cost]
GO
表格截图:
我的存储过程:
ALTER PROCEDURE [dbo].[getCrigsStaffActivity]
@ProjectRef AS VARCHAR(1000),
@staffCost AS varchar(1000)
AS
BEGIN
SET NOCOUNT ON;
DECLARE @val AS VARCHAR(2000);
SET @val='';
DECLARE @temp AS VARCHAR(2000);
DECLARE @activityLine AS VARCHAR(2000);
DECLARE @cost AS VARCHAR(2000);
DECLARE @ref as CURSOR;
SET @ref = CURSOR FOR
SELECT activityLine, cost
FROM crigsStaffActivity
WHERE projectRef = @ProjectRef
AND staffCost = @staffCost
OPEN @ref;
FETCH NEXT FROM @ref INTO @activityLine, @cost;
WHILE @@FETCH_STATUS = 0
BEGIN
FETCH NEXT FROM @ref INTO @activityLine, @cost;
SET @val = CONCAT(@activityLine,',',@cost);
END
CLOSE @ref;
DEALLOCATE @ref;
SELECT @val AS ref;
END
执行存储过程后,我得到了以下结果:
ref
----
2,2
问题在于对于项目合作者,我有两个重复的值,因此我需要获得如下结果:
ref
-----
1,1
2,2
我的问题是如何实现上述提到的结果。
这个存储过程的更好结果可能是:
ref
-----------------------------
1,1,ProjectLeader
2,2,Research collaborators
1,1,Project collaborators
2,2,Project collaborators
2,3,Research/Project Assistant