我刚开始使用pthread
,对指向指针也不是很熟悉。有没有人可以解释一下为什么pthread_join()
的第二个参数是void **
?为什么会设计成这样。
int pthread_join(pthread_t thread, void **value_ptr);
我刚开始使用pthread
,对指向指针也不是很熟悉。有没有人可以解释一下为什么pthread_join()
的第二个参数是void **
?为什么会设计成这样。
int pthread_join(pthread_t thread, void **value_ptr);
如果你想通过函数参数返回一个值,你需要传入变量的地址来接收新值。
由于pthread_join()
是设计用来接收指向pthread_exit()
传递的指针值的,该指针值是一个void*
类型,因此pthread_join()
需要一个void*
类型的地址,实际上是void**
类型。
示例:
#include <stdlib.h> /* for EXIT_xxx macros */
#include <stdio.h> /* for printf() and perror() */
#include <pthread.h>
void * tf(void * pv)
{
int * a = pv;
size_t index = 0;
printf("tf(): a[%zu] = %d\n", index , a[index]);
++index;
pthread_exit(a + index); /* Return from tf() the address of a's 2nd element.
a + 1 here is equivalent to &a[1]. */
}
int main(void)
{
int a[2] = {42, 43};
pthread_t pt;
int result = pthread_create(&pt, NULL, tf, a); /* Pass to tf() the address of
a's 1st element. a decays to
something equivalent to &a[0]. */
if (0 != result)
{
perror("pthread_create() failed");
exit(EXIT_FAILURE);
}
{
int * pi;
size_t index = 0;
{
void * pv;
result = pthread_join(pt, &pv); /* Pass in the address of a pointer-variable
pointing to where the value passed to
pthread_exit() should be written. */
if (0 != result)
{
perror("pthread_join() failed");
exit(EXIT_FAILURE);
}
pi = pv;
}
++index;
printf("main(): a[%zu] = %d\n", index, pi[0]);
}
return EXIT_SUCCESS;
}
上述程序预计将打印:
tf(): a[0] = 42
main(): a[1] = 43
// void *joinPointer; (the pointer you gave to pthread_join)
// void *exitPointer; (the pointer you gave to pthread_exit)
void pthread_exit(void *retval);
int pthread_join(pthread_t thread, void **value_ptr){
...
*value_ptr = <retval>; //retval points to what exitPointer pointed to
...
}
int main(){
...
void *joinPointer;
...
pthread_join(ithread, &joinPointer)
...
}
pthread_exit(void* retval);
和pthread_join()
应该能够传达失败信息。 - EOF