我对Python和Tkinter都比较新手,但我需要创建一个简单的表单,需要使用下拉菜单。
我尝试做类似于以下的事情:
#!/usr/bin python
import sys
from Tkinter import *
# My frame for form
class simpleform_ap(Tk):
def __init__(self,parent):
Tk.__init__(self,parent)
self.parent = parent
self.initialize()
def initialize(self):
self.grid()
# Dropdown Menu
optionList = ["Yes","No"]
self.dropVar=StringVar()
self.dropVar.set("Yes") # default choice
self.dropMenu1 = OptionMenu(self, self.dropVar, *optionList)
self.dropMenu1.grid(column=1,row=4)
print self.dropVar.get()
def create_form(argv):
form = simpleform_ap(None)
form.title('My form')
form.mainloop()
if __name__ == "__main__":
create_form(sys.argv)
然而,我所输出的始终是默认值,而不是我从下拉列表中选择的值。
我尝试使用trace方法对StringVar进行操作,做如下操作:
#!/usr/bin python
import sys
from Tkinter import *
# My frame for form
class simpleform_ap(Tk):
def __init__(self,parent):
Tk.__init__(self,parent)
self.parent = parent
self.initialize()
def initialize(self):
self.grid()
# Dropdown Menu
optionList = ["Yes","No"]
self.dropVar=StringVar()
self.dropVar.set("Yes") # default choice
self.dropMenu1 = OptionMenu(self, self.dropVar, *optionList)
self.dropMenu1.grid(column=1,row=4)
self.dropVar.trace("w",self.get_selection)
print self.dropVar.get()
def get_selection(self):
print "Selected: "+ self.dropVar.get()
def create_form(argv):
form = simpleform_ap(None)
form.title('My form')
form.mainloop()
if __name__ == "__main__":
create_form(sys.argv)
但是我收到了以下错误信息:
Exception in Tkinter callback Traceback (most recent call last):
File "/usr/lib64/python2.6/lib-tk/Tkinter.py", line 1410, in __call__
return self.func(*args) TypeError: get_selection() takes exactly 1 argument (4 given)
我做错了什么吗?
请注意,我不想使用任何按钮来确认下拉菜单中的选择。
能否给予一些建议?