描述中提到,我正在使用Android拍照。它被压缩并添加到一个
请问有人能够查看这个问题并指出我哪里做错了吗?*抱歉代码有点冗长,但是我不想错过任何帮助! ANDROID端
byte[]
中,然后进行了base64编码
。它与JSON一起发送到我的webservice,在那里它“应该”被解码并保存在SQL表行中。我可以将编码字符串保存在单独的行中,以便知道它已经传输成功。请问有人能够查看这个问题并指出我哪里做错了吗?*抱歉代码有点冗长,但是我不想错过任何帮助! ANDROID端
@Override
protected String doInBackground(String... args) {
// TODO Auto-generated method stub
// Check for success tag
int success;
stream = new ByteArrayOutputStream();
picture.compress(Bitmap.CompressFormat.JPEG, 50, stream);
image = stream.toByteArray();
String ba1 = Base64.encodeToString(image, Base64.DEFAULT);
SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(MainScreen.this);
String post_username = sp.getString("username", "anon");
try {
ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", post_username));
params.add(new BasicNameValuePair("picture", ba1));
JSONObject json = jsonParser.makeHttpRequest(POST_COMMENT_URL,
"POST", params);
success = json.getInt(TAG_SUCCESS);
if (success == 1) {
Log.d("Picture Added!", json.toString());
//finish();
return json.getString(TAG_MESSAGE);
} else {
Log.d("Upload Failure!", json.getString(TAG_MESSAGE));
return json.getString(TAG_MESSAGE);
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
protected void onPostExecute(String file_url) {
// dismiss the dialog once product deleted
pDialog.dismiss();
if (file_url != null) {
Toast.makeText(MainScreen.this, file_url, Toast.LENGTH_LONG)
.show();
}
}
}
}
PHP端
<?php
require("config.inc.php");
if (!empty($_POST)) {
$user = $_POST['username'];
$data = $_POST['picture'];
$data = base64_decode($data);
$im = imagecreatefromstring($data);
header('Content-Type: image/jpeg', true);
ob_start();
imagejpeg($im);
$imagevariable = ob_get_contents();
ob_end_clean();
$query = "INSERT INTO pictures ( username, photo, rawdata ) VALUES ( :user, :photo, :raw ) ";
$query_params = array(
':user' => $user,
':photo' => $imagevariable,
':raw' => $_POST['picture']
);
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't add post!";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Picture Successfully Added!";
echo json_encode($response);
} else {
}
?>
rawdata
在 MySQL 中被设置为什么类型的值?是 Blob 还是其他类型? - Pitchinnate