我有一组位图,它们都有一定程度的透明度,我不知道哪些部分是透明的。我想创建一个新的位图,该位图排除了透明部分,但呈正方形。这张图片应该说明了它的含义:
这是我计划这样做的方法:
这是我计划这样做的方法:
public Bitmap cutImage(Bitmap image) {
Bitmap newBitmap = null;
int width = image.getWidth();
int height = image.getHeight();
newBitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(newBitmap);
//This is where I need to find out correct values of r1 and r1.
Rect r1 = new Rect(?, ?, ?, ?);
Rect r2 = new Rect(?, ?, ?, ?);
canvas.drawBitmap(image, r1, r2, null);
return newBitmap;
}
有人知道如何实现这个吗?
编辑:
我使用以下算法找到左、右、上和下的值,已经成功实现:
private int x1;
private int x2;
private int y1;
private int y2;
private void findRectValues(Bitmap image)
{
for(int x = 0; x < image.getWidth(); x++)
{
for(int y = 0; y < image.getHeight(); y++)
{
if(image.getPixel(x, y) != Color.TRANSPARENT)
{
System.out.println("X1 is: " + x);
x1 = x;
break;
}
}
if(x1 != 0)
break;
}
for(int x = image.getWidth()-1; x > 0; x--)
{
for(int y = 0; y < image.getHeight(); y++)
{
if(image.getPixel(x, y) != Color.TRANSPARENT)
{
System.out.println("X2 is: " + x);
x2 = x;
break;
}
}
if(x2 != 0)
break;
}
for(int y = 0; y < image.getHeight(); y++)
{
for(int x = 0; x < image.getWidth(); x++)
{
if(image.getPixel(x, y) != Color.TRANSPARENT)
{
System.out.println("Y1 is: " + y);
y1 = y;
break;
}
}
if(y1 != 0)
break;
}
for(int y = image.getHeight()-1; y > 0; y--)
{
for(int x = 0; x < image.getWidth(); x++)
{
if(image.getPixel(x, y) != Color.TRANSPARENT)
{
System.out.println("Y2 is: " + y);
y2 = y;
break;
}
}
if(y2 != 0)
break;
}
}