这个有相应的特殊名称吗？也许可以类比以下内容：（已更新）
class Tree:
def __init__(self, item_or_tree):
self._setto(item_or_tree)
def __assign__(self, val):
self._setto(item_or_tree)
def __setitem__(self, which, to_what):
## I would like this to call __assign__ on the Tree object at _tree[which]
to_what._tree[which] = to_what
def __getitem__(self, which):
return self._tree[which]
def __len__(self): return len(self._tree)
def __eq__(self, other):
if isinstance(other, Tree):
if other._is_tree:
return (self._item == other._item) and (self._tree == other._tree)
else:
return self._item == other._item
else: return self._item == other
def _setto(self, item_or_tree):
if isinstance(item_or_tree, Tree):
self._set_from_Tree(item_or_tree)
elif isinstance(item_or_tree, dict):
self._set_from_dict(item_or_tree)
else:
self._set_from_other(item_or_type)
def _set_from_Tree(self, other_Tree):
self._tree = other_Tree[:]
self._item = other_Tree
self._is_tree = other_Tree._is_tree
def _set_from_dict(self, the_dict):
self._is_tree = True
self._item = None
self._tree = {}
for key, val in the_dict.items():
self._tree[key] = Tree(val)
def _set_from_other(self, other):
self._is_tree = False
self._tree = None
self._item = other
class TreeModel(Tree, QAbstractItemModel):
...
## a whole bunch of required overrides
## etc
...
我想做的是实现一个通用树形结构，它应该尽可能直观且与PyQt5的Model-View-Delegate架构无缝集成。
我希望能够将传入的item_or_tree设置为item或tree。因此，我要重载在item上使用等号（=）操作符时调用的函数。
PyQt有这种基于项目的架构，在其中覆盖了QAbstractItemModel。这应该返回/接受QModelIndex对象。这些是表格（2D数组）的树。
因此，我正在创建一个可以包含它自身、处理两种对立的索引范例并与Python和其他所有内容兼容的单一树形结构。