我使用
np.savetxt('file.txt', array, delimiter=',')
将数组保存到以逗号分隔的文件中。它看起来像这样:
1, 2, 3
4, 5, 6
7, 8, 9
我该如何将数组以numpy格式保存到文件中,使其外观与原数组一致?换句话说,它应该是这样的:
[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
我使用
np.savetxt('file.txt', array, delimiter=',')
将数组保存到以逗号分隔的文件中。它看起来像这样:
1, 2, 3
4, 5, 6
7, 8, 9
[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
In [38]: x = np.arange(1,10).reshape(3,3)
In [40]: print(np.array2string(x, separator=', '))
[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
将NumPy数组x
保存到文件中:
np.set_printoptions(threshold=np.inf, linewidth=np.inf) # turn off summarization, line-wrapping
with open(path, 'w') as f:
f.write(np.array2string(x, separator=', '))
x
保存到文件中。这对于中等大小的数组应该是有效的。然而,一个缺点是如果x
非常大,np.array2string
会生成一个巨大的字符串。这不利于内存。在这种情况下,最好遍历x
的行,并将它们分块打印出来。 - unutbu>>> from io import BytesIO
>>> bio = BytesIO('''\
... 1, 2, 3
... 4, 5, 6
... 7, 8, 9
... ''') # copy pasted from above
>>> xs = np.loadtxt(bio, delimiter=', ')
>>> xs
array([[ 1., 2., 3.],
[ 4., 5., 6.],
[ 7., 8., 9.]])
import sys
file = "<you_file_dir>file.txt"
sys.stdout = open(file, 'w')
d = [1,2,3,4,5,6,7,8,9]
l__d1 = d[0:3]
l__d2 = d[3:6]
l__d3 = d[6:9]
print str(l__d1) + '\n' + str(l__d2) + '\n' + str(l__d3)
import numpy as np
def writeLine(txt_file_path, txtArray: list):
l = len(txtArray)
counter = 0
with open(txt_file_path, 'a', encoding='utf-8') as f:
for item in txtArray:
counter += 1
row = [str(x) for x in item]
fstr = '\t'.join(row)+'\n' if counter<l else '\t'.join(row)
f.writelines(fstr)
x = np.arange(16).reshape(4,4)
writeLine('a.txt',x)