iOS - 如何沿着路径绘制渐变

5

这是我想要实现的效果:

enter image description here

这是我现在所拥有的效果:

enter image description here

基本上,我需要沿着弧线路径绘制渐变,而不是在线性方向上跨越弧线。我尝试了很多方法,其中一些产生了相同的结果,但有些则产生了与预期更远的结果。

这是我现在的代码:

    CGFloat lineSize = 12;
    CGFloat radius = self.frame.size.width/2 - lineSize;

    CGContextRef ctx = UIGraphicsGetCurrentContext();

    //Define gradient
    CGFloat colors [] =
    {
        0.9451f, 0.5804f, 0.2431f, 1.0f,
        0.9922f, 0.9490f, 0.9020f, 1.0f,
        1.0f, 1.0f, 1.0f, 1.0f,
        0.8706f, 0.9020f, 0.9412f, 1.0f,
        0.2941f, 0.6863f, 0.9176f, 1.0f
    };

    CGColorSpaceRef baseSpace = CGColorSpaceCreateDeviceRGB();
    CGGradientRef gradient = CGGradientCreateWithColorComponents(baseSpace, colors, NULL, 5);
    CGColorSpaceRelease(baseSpace), baseSpace = NULL;

    //Define arc angle and points
    CGFloat startAngle = 3.0f/4.0f * M_PI;
    CGFloat endAngle = 1.0f/4.0f * M_PI;

    CGFloat a = radius * cos(45);
    CGFloat o = a * tan(45);

    CGFloat y = CGRectGetMidY(rect) + o;

    CGPoint startPoint = CGPointMake(0, y);
    CGPoint endPoint = CGPointMake(self.frame.size.width, y);

    CGMutablePathRef arc = CGPathCreateMutable();
    CGPathAddArc(arc, NULL, CGRectGetMidX(rect), CGRectGetMidY(rect), radius,
                 startAngle, endAngle, NO);

    CGPathRef strokedArc = CGPathCreateCopyByStrokingPath(arc, NULL, 10, kCGLineCapButt, kCGLineJoinMiter, 10);

    CGContextAddPath(ctx, strokedArc);
    CGContextClip(ctx);

    CGContextDrawLinearGradient(ctx, gradient, startPoint, endPoint, 0);
    CGGradientRelease(gradient);

我也尝试更改这段代码:
CGMutablePathRef arc = CGPathCreateMutable();
    CGPathAddArc(arc, NULL, CGRectGetMidX(rect), CGRectGetMidY(rect), radius,
                 startAngle, endAngle, NO);

    CGPathRef strokedArc = CGPathCreateCopyByStrokingPath(arc, NULL, 10, kCGLineCapButt, kCGLineJoinMiter, 10);

    CGContextAddPath(ctx, strokedArc);
    CGContextClip(ctx);

    CGContextDrawLinearGradient(ctx, gradient, startPoint, endPoint, 0);
    CGGradientRelease(gradient);

转换为这个代码块:

CGContextAddArc(ctx, CGRectGetMidX(rect), CGRectGetMidY(rect), radius, startAngle, endAngle, NO);

CGContextSetLineWidth(ctx, lineSize);
CGContextSetLineCap(ctx, kCGLineCapRound);

CGContextReplacePathWithStrokedPath(ctx);
CGContextClip(ctx);

CGContextDrawLinearGradient(ctx, gradient, startPoint, endPoint, 0);
CGGradientRelease(gradient), gradient = NULL;

但是它仍然产生与我现在拥有的类似的结果。
1个回答

0

尝试通过更改渐变值来实现。

更改

 //Define gradient
    CGFloat colors [] =
    {
        0.9451f, 0.5804f, 0.2431f, 1.0f,
        0.9922f, 0.9490f, 0.9020f, 1.0f,
        1.0f, 1.0f, 1.0f, 1.0f,
        0.8706f, 0.9020f, 0.9412f, 1.0f,
        0.2941f, 0.6863f, 0.9176f, 1.0f
    };

将值转换为对称的形式。例如:

    CGFloat colors [] =
    {
        1.0f, 0.9176f, 0.6863f, 0.2941f,
        1.0f, 0.9412f, 0.9020f, 0.8706f,
        0.7432f, 1.0f, 1.0f, 0.7432f,
        0.8706f, 0.9020f, 0.9412f, 1.0f,
        0.2941f, 0.6863f, 0.9176f, 1.0f
    };

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