Python解决方案
如果您有邮政编码对应的纬度和经度,您可以使用'mpu'库直接使用Haversine公式计算它们之间的距离,该公式确定了球面上两点之间的大圆距离。
示例代码:
import mpu
zip_00501 =(40.817923,-73.045317)
zip_00544 =(40.788827,-73.039405)
dist =round(mpu.haversine_distance(zip_00501,zip_00544),2)
print(dist)
您将获得以公里为单位的结果距离。 输出:
3.27
提示:如果您没有邮政编码的相应坐标,可以使用“uszipcode”库的“SearchEngine”模块获取相同的信息(仅适用于美国邮政编码)
from uszipcode import SearchEngine
#for extensive list of zipcodes, set simple_zipcode =False
search = SearchEngine(simple_zipcode=True)
zip1 = search.by_zipcode('92708')
lat1 =zip1.lat
long1 =zip1.lng
zip2 =search.by_zipcode('53404')
lat2 =zip2.lat
long2 =zip2.lng
mpu.haversine_distance((lat1,long1),(lat2,long2))
#sample data: first three rows of data provided
df <- data.frame( zip = c( "00501", "00544", "00601" ),
longitude = c( -73.045075, -73.045147, -66.750909 ),
latitude = c( 40.816799, 40.817225, 18.181189 ),
stringsAsFactors = FALSE )
library( sf )
#create a spatial data.frame
spdf <- st_as_sf( x = df,
coords = c( "longitude", "latitude"),
crs = "+proj=longlat +datum=WGS84" )
#create the distance matrix (in meters), round to 0 decimals
m <- round( st_distance( spdf ), digits = 0 )
#set row and column names of matrix
colnames( m ) <- df$zip
rownames( m ) <- df$zip
#show distance matrix in meters
m
# Units: m
# 00501 00544 00601
# 00501 0 48 2580481
# 00544 48 0 2580528
# 00601 2580481 2580528 0
imap
包中的gdist
函数。更一般地,R中有许多GIS包,毫无疑问涉及计算速度、准确性和易用性等各种优缺点。请参考R中的GIS包。 - John Coleman