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如何旋转一个二维数组？

algorithmmatrixmultidimensional-array
359

受雷蒙德·陈的帖子的启发，假设你有一个4x4的二维数组，请编写一个将其旋转90度的函数。Raymond在其文章中提供了一种伪代码解决方案，但我想看到一些实际的东西。

[1][2][3][4]
[5][6][7][8]
[9][0][1][2]
[3][4][5][6]

变成：

[3][9][5][1]
[4][0][6][2]
[5][1][7][3]
[6][2][8][4]

更新: Nick的回答最为直接，但是有没有比n^2更好的方法呢？如果矩阵是10000x10000呢？

114
你怎么可能只用少于n^2的步骤？所有元素都必须读取和设置，而且有n^2个元素。 - erikkallen
9
您的n是多少？您没有说明2D数组是否为正方形（一般情况下并非如此！例如，向量是具有一个维度为1的矩阵），但是您似乎在暗示n是宽度和高度，并且因此有n²个元素。更合理的做法是让n成为元素数量，其中n=w×h。 - niXar
1
以下是一种快速的方法：存储行和列索引（例如 i 和 j）。转置只需要常数时间（只需交换索引即可 :)）。您可以使用旋转进行相同的操作（玩转索引）。 - mrk
4
如果n^2不可行，您可以创建一个接口来访问每个元素。然后，给定(i,j)，对(i,j)应用旋转操作以访问旋转后的元素并返回其值。这可能不是最佳解决方案，但是可以使用。 - Confuse
1
我认为你仍然可以在小于N^2的时间内完成它。但是，需要使用更复杂的数据结构。也许是某种双向链表？ - Younes Nj
显示剩余8条评论
64个回答
2

从线性的角度考虑，考虑以下矩阵：

    1 2 3        0 0 1
A = 4 5 6    B = 0 1 0
    7 8 9        1 0 0

现在对 A 求转置。
     1 4 7
A' = 2 5 8
     3 6 9

考虑A'对B的作用，或B对A'的作用。
分别为：

      7 4 1          3 6 9
A'B = 8 5 2    BA' = 2 5 8
      9 6 3          1 4 7

这适用于任何 n x n 矩阵的扩展。

在代码中快速应用这个概念：

void swapInSpace(int** mat, int r1, int c1, int r2, int c2)
{
    mat[r1][c1] ^= mat[r2][c2];
    mat[r2][c2] ^= mat[r1][c1];
    mat[r1][c1] ^= mat[r2][c2];
}

void transpose(int** mat, int size)
{
    for (int i = 0; i < size; i++)
    {
        for (int j = (i + 1); j < size; j++)
        {
            swapInSpace(mat, i, j, j, i);
        }
    }
}

void rotate(int** mat, int size)
{
    //Get transpose
    transpose(mat, size);

    //Swap columns
    for (int i = 0; i < size / 2; i++)
    {
        for (int j = 0; j < size; j++)
        {
            swapInSpace(mat, i, j, size - (i + 1), j);
        }
    }
}
2

PHP:

<?php    
$a = array(array(1,2,3,4),array(5,6,7,8),array(9,0,1,2),array(3,4,5,6));
$b = array(); //result

while(count($a)>0)
{
    $b[count($a[0])-1][] = array_shift($a[0]);
    if (count($a[0])==0)
    {
         array_shift($a);
    }
}

从PHP5.6开始，可以使用简洁的array_map()函数进行数组转置。换句话说，列被转换为行。

代码: (演示)

$array = [
    [1, 2, 3, 4],
    [5, 6, 7, 8],
    [9, 0, 1, 2],
    [3, 4, 5, 6]
];
$transposed = array_map(null, ...$array);

$transposed:

[
    [1, 5, 9, 3],
    [2, 6, 0, 4],
    [3, 7, 1, 5],
    [4, 8, 2, 6]
]
2

这是Java版本：

public static void rightRotate(int[][] matrix, int n) {
    for (int layer = 0; layer < n / 2; layer++) {
        int first = layer;
        int last = n - 1 - first;
        for (int i = first; i < last; i++) {
           int offset = i - first;
           int temp = matrix[first][i];
           matrix[first][i] = matrix[last-offset][first];
           matrix[last-offset][first] = matrix[last][last-offset];
           matrix[last][last-offset] = matrix[i][last];
           matrix[i][last] = temp;
        }
    }
}

该方法首先旋转最外层，然后按顺序移动到内层。

2
伟大的回答，但对于那些寻找DRY（Don't Repeat Yourself）JavaScript代码的人- 包括+90度和-90度旋转的情况： 

          // Input: 1 2 3
          //        4 5 6
          //        7 8 9

          // Transpose: 
          //       1 4 7
          //       2 5 8
          //       3 6 9

          // Output: 
          // +90 Degree:
          //       7 4 1
          //       8 5 2
          //       9 6 3

          // -90 Degree:
          //      3 6 9
          //      2 5 8
          //      1 4 7

          // Rotate +90
         function rotate90(matrix) {

           matrix = transpose(matrix);
           matrix.map(function(array) {
             array.reverse();
           });

           return matrix;
         }

          // Rotate -90
         function counterRotate90(matrix) {
           var result = createEmptyMatrix(matrix.length);
           matrix = transpose(matrix);
           var counter = 0;

           for (var i = matrix.length - 1; i >= 0; i--) {
             result[counter] = matrix[i];
             counter++;
           }

           return result;
         }

          // Create empty matrix
         function createEmptyMatrix(len) {
           var result = new Array();
           for (var i = 0; i < len; i++) {
             result.push([]);
           }
           return result;
         }

          // Transpose the matrix
         function transpose(matrix) {
           // make empty array
           var len = matrix.length;
           var result = createEmptyMatrix(len);

           for (var i = 0; i < matrix.length; i++) {
             for (var j = 0; j < matrix[i].length; j++) {
               var temp = matrix[i][j];
               result[j][i] = temp;
             }
           }
           return result;
         }



          // Test Cases
         var array1 = [
           [1, 2],
           [3, 4]
         ];
         var array2 = [
           [1, 2, 3],
           [4, 5, 6],
           [7, 8, 9]
         ];
         var array3 = [
           [1, 2, 3, 4],
           [5, 6, 7, 8],
           [9, 10, 11, 12],
           [13, 14, 15, 16]
         ];

          // +90 degress Rotation Tests

         var test1 = rotate90(array1);
         var test2 = rotate90(array2);
         var test3 = rotate90(array3);
         console.log(test1);
         console.log(test2);
         console.log(test3);

          // -90 degress Rotation Tests
         var test1 = counterRotate90(array1);
         var test2 = counterRotate90(array2);
         var test3 = counterRotate90(array3);
         console.log(test1);
         console.log(test2);
         console.log(test3);

2

以下是我的C语言实现，O(1)内存复杂度，对原数组进行就地旋转，顺时针旋转90度：

#include <stdio.h>

#define M_SIZE 5

static void initMatrix();
static void printMatrix();
static void rotateMatrix();

static int m[M_SIZE][M_SIZE];

int main(void){
    initMatrix();
    printMatrix();
    rotateMatrix();
    printMatrix();

    return 0;
}

static void initMatrix(){
    int i, j;

    for(i = 0; i < M_SIZE; i++){
        for(j = 0; j < M_SIZE; j++){
            m[i][j] = M_SIZE*i + j + 1;
        }
    }
}

static void printMatrix(){
    int i, j;

    printf("Matrix\n");
    for(i = 0; i < M_SIZE; i++){
        for(j = 0; j < M_SIZE; j++){
            printf("%02d ", m[i][j]);
        }
        printf("\n");
    }
    printf("\n");
}

static void rotateMatrix(){
    int r, c;

    for(r = 0; r < M_SIZE/2; r++){
        for(c = r; c < M_SIZE - r - 1; c++){
            int tmp = m[r][c];

            m[r][c] = m[M_SIZE - c - 1][r];
            m[M_SIZE - c - 1][r] = m[M_SIZE - r - 1][M_SIZE - c - 1];
            m[M_SIZE - r - 1][M_SIZE - c - 1] = m[c][M_SIZE - r - 1];
            m[c][M_SIZE - r - 1] = tmp;
        }
    }
}
2

以下是用C#编写的将二维数组[n,m]向右旋转90度的代码：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace MatrixProject
{
    // mattrix class

    class Matrix{
        private int rows;
        private int cols;
        private int[,] matrix;

        public Matrix(int n){
            this.rows = n;
            this.cols = n;
            this.matrix = new int[this.rows,this.cols];

        }

        public Matrix(int n,int m){
            this.rows = n;
            this.cols = m;

            this.matrix = new int[this.rows,this.cols];
        }

        public void Show()
        {
            for (var i = 0; i < this.rows; i++)
            {
                for (var j = 0; j < this.cols; j++) {
                    Console.Write("{0,3}", this.matrix[i, j]);
                }
                Console.WriteLine();
            }                
        }

        public void ReadElements()
        {
           for (var i = 0; i < this.rows; i++)
                for (var j = 0; j < this.cols; j++)
                {
                    Console.Write("element[{0},{1}]=",i,j);
                    this.matrix[i, j] = Convert.ToInt32(Console.ReadLine());
                }            
        }


        // rotate [n,m] 2D array by 90 deg right
        public void Rotate90DegRight()
        {

            // create a mirror of current matrix
            int[,] mirror = this.matrix;

            // create a new matrix
            this.matrix = new int[this.cols, this.rows];

            for (int i = 0; i < this.rows; i++)
            {
                for (int j = 0; j < this.cols; j++)
                {
                    this.matrix[j, this.rows - i - 1] = mirror[i, j];
                }
            }

            // replace cols count with rows count
            int tmp = this.rows;
            this.rows = this.cols;
            this.cols = tmp;           
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Matrix myMatrix = new Matrix(3,4);
            Console.WriteLine("Enter matrix elements:");
            myMatrix.ReadElements();
            Console.WriteLine("Matrix elements are:");
            myMatrix.Show();
            myMatrix.Rotate90DegRight();
            Console.WriteLine("Matrix rotated at 90 deg are:");
            myMatrix.Show();
            Console.ReadLine();
        }
    }
}

结果：

    Enter matrix elements:
    element[0,0]=1
    element[0,1]=2
    element[0,2]=3
    element[0,3]=4
    element[1,0]=5
    element[1,1]=6
    element[1,2]=7
    element[1,3]=8
    element[2,0]=9
    element[2,1]=10
    element[2,2]=11
    element[2,3]=12
    Matrix elements are:
      1  2  3  4
      5  6  7  8
      9 10 11 12
    Matrix rotated at 90 deg are:
      9  5  1
     10  6  2
     11  7  3
     12  8  4
1

矩阵转置和旋转（+/-90，+/-180）的C代码

  • 支持正方形和非正方形矩阵，具有原地和复制功能
  • 支持使用逻辑行/列的2D数组和1D指针
  • 单元测试；请参见测试以获取使用示例
  • 经过gcc -std=c90 -Wall -pedantic、MSVC17测试

`

#include <stdlib.h>
#include <memory.h>
#include <assert.h>

/* 
    Matrix transpose & rotate (+/-90, +/-180)
        Supports both 2D arrays and 1D pointers with logical rows/cols
        Supports square and non-square matrices, has in-place and copy features
        See tests for examples of usage
    tested gcc -std=c90 -Wall -pedantic, MSVC17
*/

typedef int matrix_data_t;  /* matrix data type */

void transpose(const matrix_data_t* src, matrix_data_t* dst, int rows, int cols);
void transpose_inplace(matrix_data_t* data, int n );
void rotate(int direction, const matrix_data_t* src, matrix_data_t* dst, int rows, int cols);
void rotate_inplace(int direction, matrix_data_t* data, int n);
void reverse_rows(matrix_data_t* data, int rows, int cols);
void reverse_cols(matrix_data_t* data, int rows, int cols);

/* test/compare fn */
int test_cmp(const matrix_data_t* lhs, const matrix_data_t* rhs, int rows, int cols );

/* TESTS/USAGE */
void transpose_test() {

    matrix_data_t sq3x3[9] = { 0,1,2,3,4,5,6,7,8 };/* 3x3 square, odd length side */
    matrix_data_t sq3x3_cpy[9];
    matrix_data_t sq3x3_2D[3][3] = { { 0,1,2 },{ 3,4,5 },{ 6,7,8 } };/* 2D 3x3 square */
    matrix_data_t sq3x3_2D_copy[3][3];

    /* expected test values */
    const matrix_data_t sq3x3_orig[9] = { 0,1,2,3,4,5,6,7,8 };
    const matrix_data_t sq3x3_transposed[9] = { 0,3,6,1,4,7,2,5,8};

    matrix_data_t sq4x4[16]= { 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 };/* 4x4 square, even length*/
    const matrix_data_t sq4x4_orig[16] = { 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 };
    const matrix_data_t sq4x4_transposed[16] = { 0,4,8,12,1,5,9,13,2,6,10,14,3,7,11,15 };

    /* 2x3 rectangle */
    const matrix_data_t r2x3_orig[6] = { 0,1,2,3,4,5 };
    const matrix_data_t r2x3_transposed[6] = { 0,3,1,4,2,5 };
    matrix_data_t r2x3_copy[6];

    matrix_data_t r2x3_2D[2][3] = { {0,1,2},{3,4,5} };  /* 2x3 2D rectangle */
    matrix_data_t r2x3_2D_t[3][2];

    /* matrix_data_t r3x2[6] = { 0,1,2,3,4,5 }; */
    matrix_data_t r3x2_copy[6];
    /* 3x2 rectangle */
    const matrix_data_t r3x2_orig[6] = { 0,1,2,3,4,5 };
    const matrix_data_t r3x2_transposed[6] = { 0,2,4,1,3,5 };

    matrix_data_t r6x1[6] = { 0,1,2,3,4,5 };    /* 6x1 */
    matrix_data_t r6x1_copy[6];

    matrix_data_t r1x1[1] = { 0 };  /*1x1*/
    matrix_data_t r1x1_copy[1];

    /* 3x3 tests, 2D array tests */
    transpose_inplace(sq3x3, 3);    /* transpose in place */
    assert(!test_cmp(sq3x3, sq3x3_transposed, 3, 3));
    transpose_inplace(sq3x3, 3);    /* transpose again */
    assert(!test_cmp(sq3x3, sq3x3_orig, 3, 3));

    transpose(sq3x3, sq3x3_cpy, 3, 3);  /* transpose copy 3x3*/
    assert(!test_cmp(sq3x3_cpy, sq3x3_transposed, 3, 3));

    transpose((matrix_data_t*)sq3x3_2D, (matrix_data_t*)sq3x3_2D_copy, 3, 3);   /* 2D array transpose/copy */
    assert(!test_cmp((matrix_data_t*)sq3x3_2D_copy, sq3x3_transposed, 3, 3));
    transpose_inplace((matrix_data_t*)sq3x3_2D_copy, 3);    /* 2D array transpose in place */
    assert(!test_cmp((matrix_data_t*)sq3x3_2D_copy, sq3x3_orig, 3, 3));

    /* 4x4 tests */
    transpose_inplace(sq4x4, 4);    /* transpose in place */
    assert(!test_cmp(sq4x4, sq4x4_transposed, 4,4));
    transpose_inplace(sq4x4, 4);    /* transpose again */
    assert(!test_cmp(sq4x4, sq4x4_orig, 3, 3));

    /* 2x3,3x2 tests */
    transpose(r2x3_orig, r2x3_copy, 2, 3);
    assert(!test_cmp(r2x3_copy, r2x3_transposed, 3, 2));

    transpose(r3x2_orig, r3x2_copy, 3, 2);
    assert(!test_cmp(r3x2_copy, r3x2_transposed, 2,3));

    /* 2D array */
    transpose((matrix_data_t*)r2x3_2D, (matrix_data_t*)r2x3_2D_t, 2, 3);
    assert(!test_cmp((matrix_data_t*)r2x3_2D_t, r2x3_transposed, 3,2));

    /* Nx1 test, 1x1 test */
    transpose(r6x1, r6x1_copy, 6, 1);
    assert(!test_cmp(r6x1_copy, r6x1, 1, 6));

    transpose(r1x1, r1x1_copy, 1, 1);
    assert(!test_cmp(r1x1_copy, r1x1, 1, 1));

}

void rotate_test() {

    /* 3x3 square */
    const matrix_data_t sq3x3[9] = { 0,1,2,3,4,5,6,7,8 };
    const matrix_data_t sq3x3_r90[9] = { 6,3,0,7,4,1,8,5,2 };
    const matrix_data_t sq3x3_180[9] = { 8,7,6,5,4,3,2,1,0 };
    const matrix_data_t sq3x3_l90[9] = { 2,5,8,1,4,7,0,3,6 };
    matrix_data_t sq3x3_copy[9];

    /* 3x3 square, 2D */
    matrix_data_t sq3x3_2D[3][3] = { { 0,1,2 },{ 3,4,5 },{ 6,7,8 } };

    /* 4x4, 2D */
    matrix_data_t sq4x4[4][4] = { { 0,1,2,3 },{ 4,5,6,7 },{ 8,9,10,11 },{ 12,13,14,15 } };
    matrix_data_t sq4x4_copy[4][4];
    const matrix_data_t sq4x4_r90[16] = { 12,8,4,0,13,9,5,1,14,10,6,2,15,11,7,3 };
    const matrix_data_t sq4x4_l90[16] = { 3,7,11,15,2,6,10,14,1,5,9,13,0,4,8,12 };
    const matrix_data_t sq4x4_180[16] = { 15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0 };

    matrix_data_t r6[6] = { 0,1,2,3,4,5 };  /* rectangle with area of 6 (1x6,2x3,3x2, or 6x1) */
    matrix_data_t r6_copy[6];
    const matrix_data_t r1x6_r90[6] = { 0,1,2,3,4,5 };
    const matrix_data_t r1x6_l90[6] = { 5,4,3,2,1,0 };
    const matrix_data_t r1x6_180[6] = { 5,4,3,2,1,0 };

    const matrix_data_t r2x3_r90[6] = { 3,0,4,1,5,2 };
    const matrix_data_t r2x3_l90[6] = { 2,5,1,4,0,3 };
    const matrix_data_t r2x3_180[6] = { 5,4,3,2,1,0 };

    const matrix_data_t r3x2_r90[6] = { 4,2,0,5,3,1 };
    const matrix_data_t r3x2_l90[6] = { 1,3,5,0,2,4 };
    const matrix_data_t r3x2_180[6] = { 5,4,3,2,1,0 };

    const matrix_data_t r6x1_r90[6] = { 5,4,3,2,1,0 };
    const matrix_data_t r6x1_l90[6] = { 0,1,2,3,4,5 };
    const matrix_data_t r6x1_180[6] = { 5,4,3,2,1,0 };

    /* sq3x3 tests */
    rotate(90, sq3x3, sq3x3_copy, 3, 3);    /* +90 */
    assert(!test_cmp(sq3x3_copy, sq3x3_r90, 3, 3));
    rotate(-90, sq3x3, sq3x3_copy, 3, 3);   /* -90 */
    assert(!test_cmp(sq3x3_copy, sq3x3_l90, 3, 3));
    rotate(180, sq3x3, sq3x3_copy, 3, 3);   /* 180 */
    assert(!test_cmp(sq3x3_copy, sq3x3_180, 3, 3));
    /* sq3x3 in-place rotations */
    memcpy( sq3x3_copy, sq3x3, 3 * 3 * sizeof(matrix_data_t));
    rotate_inplace(90, sq3x3_copy, 3);
    assert(!test_cmp(sq3x3_copy, sq3x3_r90, 3, 3));
    rotate_inplace(-90, sq3x3_copy, 3);
    assert(!test_cmp(sq3x3_copy, sq3x3, 3, 3)); /* back to 0 orientation */
    rotate_inplace(180, sq3x3_copy, 3);
    assert(!test_cmp(sq3x3_copy, sq3x3_180, 3, 3));
    rotate_inplace(-180, sq3x3_copy, 3);
    assert(!test_cmp(sq3x3_copy, sq3x3, 3, 3));
    rotate_inplace(180, (matrix_data_t*)sq3x3_2D, 3);/* 2D test */
    assert(!test_cmp((matrix_data_t*)sq3x3_2D, sq3x3_180, 3, 3));

    /* sq4x4 */
    rotate(90, (matrix_data_t*)sq4x4, (matrix_data_t*)sq4x4_copy, 4, 4);
    assert(!test_cmp((matrix_data_t*)sq4x4_copy, sq4x4_r90, 4, 4));
    rotate(-90, (matrix_data_t*)sq4x4, (matrix_data_t*)sq4x4_copy, 4, 4);
    assert(!test_cmp((matrix_data_t*)sq4x4_copy, sq4x4_l90, 4, 4));
    rotate(180, (matrix_data_t*)sq4x4, (matrix_data_t*)sq4x4_copy, 4, 4);
    assert(!test_cmp((matrix_data_t*)sq4x4_copy, sq4x4_180, 4, 4));

    /* r6 as 1x6 */
    rotate(90, r6, r6_copy, 1, 6);
    assert(!test_cmp(r6_copy, r1x6_r90, 1, 6));
    rotate(-90, r6, r6_copy, 1, 6);
    assert(!test_cmp(r6_copy, r1x6_l90, 1, 6));
    rotate(180, r6, r6_copy, 1, 6);
    assert(!test_cmp(r6_copy, r1x6_180, 1, 6));

    /* r6 as 2x3 */
    rotate(90, r6, r6_copy, 2, 3);
    assert(!test_cmp(r6_copy, r2x3_r90, 2, 3));
    rotate(-90, r6, r6_copy, 2, 3);
    assert(!test_cmp(r6_copy, r2x3_l90, 2, 3));
    rotate(180, r6, r6_copy, 2, 3);
    assert(!test_cmp(r6_copy, r2x3_180, 2, 3));

    /* r6 as 3x2 */
    rotate(90, r6, r6_copy, 3, 2);
    assert(!test_cmp(r6_copy, r3x2_r90, 3, 2));
    rotate(-90, r6, r6_copy, 3, 2);
    assert(!test_cmp(r6_copy, r3x2_l90, 3, 2));
    rotate(180, r6, r6_copy, 3, 2);
    assert(!test_cmp(r6_copy, r3x2_180, 3, 2));

    /* r6 as 6x1 */
    rotate(90, r6, r6_copy, 6, 1);
    assert(!test_cmp(r6_copy, r6x1_r90, 6, 1));
    rotate(-90, r6, r6_copy, 6, 1);
    assert(!test_cmp(r6_copy, r6x1_l90, 6, 1));
    rotate(180, r6, r6_copy, 6, 1);
    assert(!test_cmp(r6_copy, r6x1_180, 6, 1));
}

/* test comparison fn, return 0 on match else non zero */
int test_cmp(const matrix_data_t* lhs, const matrix_data_t* rhs, int rows, int cols) {

    int r, c;

    for (r = 0; r < rows; ++r) {
        for (c = 0; c < cols; ++c) {
            if ((lhs + r * cols)[c] != (rhs + r * cols)[c])
                return -1;
        }
    }
    return 0;
}

/*
Reverse values in place of each row in 2D matrix data[rows][cols] or in 1D pointer with logical rows/cols
[A B C] ->  [C B A]
[D E F]     [F E D]
*/
void reverse_rows(matrix_data_t* data, int rows, int cols) {

    int r, c;
    matrix_data_t temp;
    matrix_data_t* pRow = NULL;

    for (r = 0; r < rows; ++r) {
        pRow = (data + r * cols);
        for (c = 0; c < (int)(cols / 2); ++c) { /* explicit truncate */
            temp = pRow[c];
            pRow[c] = pRow[cols - 1 - c];
            pRow[cols - 1 - c] = temp;
        }
    }
}

/*
Reverse values in place of each column in 2D matrix data[rows][cols] or in 1D pointer with logical rows/cols
[A B C] ->  [D E F]
[D E F]     [A B C]
*/
void reverse_cols(matrix_data_t* data, int rows, int cols) {

    int r, c;
    matrix_data_t temp;
    matrix_data_t* pRowA = NULL;
    matrix_data_t* pRowB = NULL;

    for (c = 0; c < cols; ++c) {
        for (r = 0; r < (int)(rows / 2); ++r) { /* explicit truncate */
            pRowA = data + r * cols;
            pRowB = data + cols * (rows - 1 - r);
            temp = pRowA[c];
            pRowA[c] = pRowB[c];
            pRowB[c] = temp;
        }
    }
}

/* Transpose NxM matrix to MxN matrix in O(n) time */
void transpose(const matrix_data_t* src, matrix_data_t* dst, int N, int M) {

    int i;
    for (i = 0; i<N*M; ++i) dst[(i%M)*N + (i / M)] = src[i];    /* one-liner version */

    /*
    expanded version of one-liner:  calculate XY based on array index, then convert that to YX array index
    int i,j,x,y;
    for (i = 0; i < N*M; ++i) {
    x = i % M;
    y = (int)(i / M);
    j = x * N + y;
    dst[j] = src[i];
    }
    */

    /*
    nested for loop version
    using ptr arithmetic to get proper row/column
    this is really just dst[col][row]=src[row][col]

    int r, c;

    for (r = 0; r < rows; ++r) {
        for (c = 0; c < cols; ++c) {
            (dst + c * rows)[r] = (src + r * cols)[c];
        }
    }
    */
}

/*
Transpose NxN matrix in place
*/
void transpose_inplace(matrix_data_t* data, int N ) {

    int r, c;
    matrix_data_t temp;

    for (r = 0; r < N; ++r) {
        for (c = r; c < N; ++c) { /*start at column=row*/
                                    /* using ptr arithmetic to get proper row/column */
                                    /* this is really just
                                    temp=dst[col][row];
                                    dst[col][row]=src[row][col];
                                    src[row][col]=temp;
                                    */
            temp = (data + c * N)[r];
            (data + c * N)[r] = (data + r * N)[c];
            (data + r * N)[c] = temp;
        }
    }
}

/*
Rotate 1D or 2D src matrix to dst matrix in a direction (90,180,-90)
Precondition:  src and dst are 2d matrices with dimensions src[rows][cols] and dst[cols][rows] or 1D pointers with logical rows/cols
*/
void rotate(int direction, const matrix_data_t* src, matrix_data_t* dst, int rows, int cols) {

    switch (direction) {
    case -90:
        transpose(src, dst, rows, cols);
        reverse_cols(dst, cols, rows);
        break;
    case 90:
        transpose(src, dst, rows, cols);
        reverse_rows(dst, cols, rows);
        break;
    case 180:
    case -180:
        /* bit copy to dst, use in-place reversals */
        memcpy(dst, src, rows*cols*sizeof(matrix_data_t));
        reverse_cols(dst, cols, rows);
        reverse_rows(dst, cols, rows);
        break;
    }
}

/*
Rotate array in a direction.
Array must be NxN 2D or 1D array with logical rows/cols
Direction can be (90,180,-90,-180)
*/
void rotate_inplace( int direction, matrix_data_t* data, int n) {

    switch (direction) {
    case -90:
        transpose_inplace(data, n);
        reverse_cols(data, n, n);
        break;
    case 90:
        transpose_inplace(data, n);
        reverse_rows(data, n, n);
        break;
    case 180:
    case -180:
        reverse_cols(data, n, n);
        reverse_rows(data, n, n);
        break;
    }
}

`

1

PHP解决方案，用于顺时针和逆时针

$aMatrix = array(
    array( 1, 2, 3 ),
    array( 4, 5, 6 ),
    array( 7, 8, 9 )
    );

function CounterClockwise( $aMatrix )
{
    $iCount  = count( $aMatrix );
    $aReturn = array();
    for( $y = 0; $y < $iCount; ++$y )
    {
        for( $x = 0; $x < $iCount; ++$x )
        {
            $aReturn[ $iCount - $x - 1 ][ $y ] = $aMatrix[ $y ][ $x ];
        }
    }
    return $aReturn;
}

function Clockwise( $aMatrix )
{
    $iCount  = count( $aMatrix );
    $aReturn = array();
    for( $y = 0; $y < $iCount; ++$y )
    {
        for( $x = 0; $x < $iCount; ++$x )
        {
            $aReturn[ $x ][ $iCount - $y - 1 ] = $aMatrix[ $y ][ $x ];
        }
    }
    return $aReturn;
}

function printMatrix( $aMatrix )
{
    $iCount = count( $aMatrix );
    for( $x = 0; $x < $iCount; ++$x )
    {
        for( $y = 0; $y < $iCount; ++$y )
        {
            echo $aMatrix[ $x ][ $y ];
            echo " ";
        }
        echo "\n";
    }
}
printMatrix( $aMatrix );
echo "\n";
$aNewMatrix = CounterClockwise( $aMatrix );
printMatrix( $aNewMatrix );
echo "\n";
$aNewMatrix = Clockwise( $aMatrix );
printMatrix( $aNewMatrix );
1

#transpose是Ruby的Array类的标准方法，因此：

% irb
irb(main):001:0> m = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 0, 1, 2], [3, 4, 5, 6]]
=> [[1, 2, 3, 4], [5, 6, 7, 8], [9, 0, 1, 2], [3, 4, 5, 6]] 
irb(main):002:0> m.reverse.transpose
=> [[3, 9, 5, 1], [4, 0, 6, 2], [5, 1, 7, 3], [6, 2, 8, 4]]

实现是一个用C语言编写的n^2转置函数。您可以在此处查看它： http://www.ruby-doc.org/core-1.9.3/Array.html#method-i-transpose 通过选择“transpose”旁边的“click to toggle source”。
我记得有比O(n^2)更好的解决方案，但仅适用于特殊构造的矩阵（如稀疏矩阵）。
1

这是一个用于任意M*N矩阵原地顺时针旋转90度的C代码

void rotateInPlace(int * arr[size][size], int row, int column){
    int i, j;
    int temp = row>column?row:column;
    int flipTill = row < column ? row : column;
    for(i=0;i<flipTill;i++){
        for(j=0;j<i;j++){
            swapArrayElements(arr, i, j);
        }
    }

    temp = j+1;

    for(i = row>column?i:0; i<row; i++){
            for(j=row<column?temp:0; j<column; j++){
                swapArrayElements(arr, i, j);
            }
    }

    for(i=0;i<column;i++){
        for(j=0;j<row/2;j++){
            temp = arr[i][j];
            arr[i][j] = arr[i][row-j-1];
            arr[i][row-j-1] = temp;
        }
    }
}
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