如何使用Python和numpy库将 a 数组转换为下面指定的 b 数组?我正在寻找一种非常高效的方式,因为我要在实际数组上使用这种方法很大。我应该提到,数字可以是任何数,并且数字之间没有关系。另外,我尝试在下面的图片中展示了我希望如何切片数组。
import numpy as np
a = np.arange(1, 49).reshape(6, 8)
a = [[ 1, 2, 3, 4, 5, 6, 7, 8],
[ 9, 10, 11, 12, 13, 14, 15, 16],
[17, 18, 19, 20, 21, 22, 23, 24],
[25, 26, 27, 28, 29, 30, 31, 32],
[33, 34, 35, 36, 37, 38, 39, 40],
[41, 42, 43, 44, 45, 46, 47, 48]]
b =[[1, 2, 9, 10], [2, 3, 10, 11], [3, 4, 11, 12], [4, 5, 12, 13],
[5, 6, 13, 14], [6, 7, 14, 15], [7, 8, 15, 16], [9, 10, 17, 18],
[10, 11, 18, 19], [11, 12, 19, 20], [12, 13, 20, 21], [13, 14, 21, 22],
[14, 15, 22, 23], [15, 16, 23, 24], [17, 18, 25, 26], [18, 19, 26, 27],
[19, 20, 27, 28], [20, 21, 28, 29], [21, 22, 29, 30], [22, 23, 30, 31],
[23, 24, 31, 32], [25, 26, 33, 34], [26, 27, 34, 35], [27, 28, 35, 36],
[28, 29, 36, 37], [29, 30, 37, 38], [30, 31, 38, 39], [31, 32, 39, 40],
[33, 34, 41, 42], [34, 35, 42, 43], [35, 36, 43, 44], [36, 37, 44, 45],
[37, 38, 45, 46], [38, 39, 46, 47], [39, 40, 47, 48]]
我试图使用reshape和transpose函数来解决问题,但是我无法找到一种方法来包括边界。c显示了我的解决思路。
c = a.reshape(3, 2, 4, 2).transpose(0, 2, 3, 1).reshape(3*4, 2*2).
图片链接:https://ibb.co/QC7tkPM。
as_strided
的函数可以制作重叠块,用于像移动平均这样的事情。更新版本具有导数windowing
函数。 - hpaulj