如何从嵌入在父视图控制器的子视图控制器中的UISearchViewController中呈现一个视图控制器?

3
我有一个父视图控制器叫做MainViewController,和一个子视图控制器叫做FilterViewController,它只占用主控制器屏幕的部分。

在filterViewController中,我向tableview添加了一个UISearchController。但是当我点击搜索结果时要前往DetailViewController

Attempt to present <MyApp.DetailViewController: 0x7f97ae057780> on <MyApp.FilterViewController: 0x7f97abd62b40> which is already presenting <UISearchController: 0x7f97abd85270>

我正在iPad iOS 8模拟器上使用此功能。 如果resultSearchController未激活,则可以单击表格并转到我想要的任何内容,但某种程度上,这个uisearchcontroller不允许我这样做,有没有解决方法?

代码: MainViewController.swift

   func addFilterViewController(){
    filterViewController = self.storyboard?.instantiateViewControllerWithIdentifier("filterviewcontroller") as! FilterViewController
    filterViewController.mainViewController = self
    self.addChildViewController(filterViewController)
    filterViewController.view.frame = CGRectMake(self.view.frame.width*2/3, 0, self.view.frame.width/3, self.view.frame.height)
    self.view.addSubview(filterViewController.view)
    filterViewController.didMoveToParentViewController(self)
}

FilterViewController.swift

func setUpSearchBar() {
    resultSearchController = UISearchController(searchResultsController: nil)
    resultSearchController.searchResultsUpdater = self
    resultSearchController.dimsBackgroundDuringPresentation = false

    let searchBar = self.resultSearchController.searchBar
    searchBar.sizeToFit()
    searchBar.backgroundImage = UIImage()
    searchBar.barTintColor = UIColor.clearColor()
    searchBar.backgroundColor = UIColor.lightBlue()
    searchBar.placeholder = "Type to search"
    filterTable.tableHeaderView = searchBar
}

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    if resultSearchController.active {
        println("search table select")
        let detailVC = self.storyboard?.instantiateViewControllerWithIdentifier("detailViewController") as! DetailViewController
        detailVC.card = filteredCards[indexPath.row]

        // this has same problem if I pass in the MainViewController and do mainViewController.presentViewController...
        self.presentViewController(detailVC, animated: false, completion: nil)

    } else {
        // other code
    }

    filterTable.deselectRowAtIndexPath(indexPath, animated: true)
}

func updateSearchResultsForSearchController(searchController: UISearchController) {
    self.filteredCards = self.unorderedCards.filter{
        (card: Card) -> Bool in
        let name = card.firstName + card.lastName
        let stringMatch = tributeName.lowercaseString.rangeOfString(searchController.searchBar.text.lowercaseString)
        return (stringMatch != nil)
    }
    filterTable.reloadData()

}

 func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
  if resultSearchController.active {
       return filteredCards.count
   } else {
       return unOrderedCards.count
   }}


func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier("filtercell", forIndexPath: indexPath) as! FilterCell
    cell.backgroundColor = UIColor.lightBlue()
    if resultSearchController.active {

        let card = filteredCards[indexPath.row]
        cell.name.text = card.firstName

    } else {
        let card = unOrderedCards[indexPath.row]
        cell.name.text = card.firstName
    }
    return cell
}
1个回答

1

如果问题在于视图控制器尚未呈现resultSearchController,为什么不让resultSearchController呈现新的vc?

resultSearchController.presentViewController(detailVC, animated: false, completion: nil)

如果您需要从resultSearchController中进行dismiss操作,只需创建一个继承自UISearchController的新类。


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