请考虑下面的代码:
import java.util.*;
class Employee {
String name;
public Employee(String nm) {
this.name=nm;
}
}
public class HashMapKeyNullValue {
Employee e1;
public void display(){
Employee e2=null;
Map map=new HashMap();
map.put(e2, "25");
System.out.println("Getting the Value When e2 is set as KEY");
System.out.println("e2 : "+map.get(e2));
System.out.println("e1 : "+map.get(e1));
System.out.println("null : "+map.get(null));
map.put(e1, "");
System.out.println("Getting the Value when e1 is set as KEY");
System.out.println("e2 : "+map.get(e2));
System.out.println("e1 : "+map.get(e1));
System.out.println("null : "+map.get(null));
map.put(null, null); // null as key and null as value
System.out.println("Getting the Value when setting null as KEY and null as value");
System.out.println("e2 : "+map.get(e2));
System.out.println("e1 : "+map.get(e1));
System.out.println("null : "+map.get(null));
map.put(null, "30");
System.out.println("Getting the Value when setting only null as KEY");
System.out.println("e2 : "+map.get(e2));
System.out.println("e1 : "+map.get(e1));
System.out.println("null : "+map.get(null));
}
public static void main(String[] args) {
new HashMapKeyNullValue().display();
}
}
程序的输出为:
Getting the Value When e2 is set as KEY
e2 : 25
e1 : 25
null : 25
Getting the Value when e1 is set as KEY
e2 :
e1 :
null :
Getting the Value when setting null as KEY and null as value
e2 : null
e1 : null
null : null
Getting the Value when setting only null as KEY
e2 : 30
e1 : 30
null : 30
这里介绍了e1,e2和null
作为键的关系。它们是否都分配给相同的哈希码?如果是,为什么?
由于这三个值看起来都不同,更改其中一个值会更改其他值。这是否意味着只有一个键的条目被添加到HashMap
中,即e1,e2或null
?因为它们都被视为相同的键。