这些都帮助我达到了这个目标。虽然我仍在使用2012版本,但现在我有了一个快速的方法,可以分割一个字符串,即使该字符串具有不同数量的分隔符,并从该字符串中获取第n个子字符串。它也很快。我知道这篇文章已经过时了,但我花了很长时间才找到这个方法,希望能帮助其他人。
CREATE FUNCTION [dbo].[SplitsByIndex]
(@separator VARCHAR(20) = ' ',
@string VARCHAR(MAX),
@position INT
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE @results TABLE
(id INT IDENTITY(1, 1),
chrs VARCHAR(8000)
);
DECLARE @outResult VARCHAR(8000);
WITH X(N)
AS (SELECT 'Table1'
FROM(VALUES(0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0)) T(C)),
Y(N)
AS (SELECT 'Table2'
FROM X A1,
X A2,
X A3,
X A4,
X A5,
X A6,
X A7,
X A8),
T(N)
AS (SELECT TOP (ISNULL(LEN(@string), 0)) ROW_NUMBER() OVER(
ORDER BY
(
SELECT NULL
)) - 1 N
FROM Y),
Delim(Pos)
AS (SELECT t.N
FROM T
WHERE(SUBSTRING(@string, t.N, LEN(@separator + 'x') - 1) LIKE @separator
OR t.N = 0)),
Separated(value)
AS (SELECT SUBSTRING(@string, d.Pos + LEN(@separator + 'x') - 1, LEAD(d.Pos, 1, 2147483647) OVER(
ORDER BY
(
SELECT NULL
))-d.Pos - LEN(@separator))
FROM Delim d
WHERE @string IS NOT NULL)
INSERT INTO @results(chrs)
SELECT s.value
FROM Separated s
WHERE s.value <> @separator;
SELECT @outResult =
(
SELECT chrs
FROM @results
WHERE id = @position
);
RETURN @outResult;
END;
这可以这样使用:
SELECT [dbo].[SplitsByIndex](' ',fieldname,2)
from tablename