我正在构建一个名为C--（不是真正的C--语言）的虚构编程语言的解析器。我已经到了需要将语言的语法转换成Pyparsing可以接受的东西的阶段。不幸的是，当我来解析我的输入字符串（该字符串正确并且不应导致Pyparsing出错）时，它无法正确解析。我担心这是由于我的语法存在错误，但由于我第一次使用Pyparsing，我似乎看不到自己的错误在哪里。
我已经上传了我正在转换的语法这里供大家阅读。
编辑: 已根据Paul的建议更新。
这是我目前拥有的语法（语法定义的前两行非常糟糕，我知道）：
# Lexical structure definition
ifS = Keyword('if')
elseS = Keyword('else')
whileS = Keyword('while')
returnS = Keyword('return')
intVar = Keyword('int')
voidKeyword = Keyword('void')
sumdiff = Literal('+') | Literal('-')
prodquot = Literal('*') | Literal('/')
relation = Literal('<=') | Literal('<') | Literal('==') | \
Literal('!=') | Literal('>') | Literal('=>')
lbrace = Literal('{')
rbrace = Literal('}')
lparn = Literal('(')
rparn = Literal(')')
semi = Literal(';')
comma = Literal(',')
number = Word(nums)
identifier = Word(alphas, alphanums)
# Syntax definition
term = ''
statement = ''
variable = intVar + identifier + semi
locals = ZeroOrMore(variable)
expr = term | OneOrMore(Group(sumdiff + term))
args = ZeroOrMore(OneOrMore(Group(expr + comma)) | expr)
funccall = Group(identifier + lparn + args + rparn)
factor = Group(lparn + expr + rparn) | identifier | funccall | number
term = factor | OneOrMore(prodquot + factor)
cond = Group(lparn + expr + relation + expr + rparn)
returnState = Group(returnS + semi) | Combine(returnS + expr + semi)
assignment = Group(identifier + '=' + expr + semi)
proccall = Group(identifier + lparn + args + rparn + semi)
block = Group(lbrace + locals + statement + rbrace)
iteration = Group(whileS + cond + block)
selection = Group(ifS + cond + block) | Group(ifS + cond + block + elseS + block)
statement = OneOrMore(proccall | assignment | selection | iteration | returnState)
param = Group(intVar + identifier)
paramlist = OneOrMore(Combine(param + comma)) | param
params = paramlist | voidKeyword
procedure = Group(voidKeyword + identifier + lparn + params + rparn + block)
function = Group(intVar + identifier + lparn + params + rparn + block)
declaration = variable | function | procedure
program = OneOrMore(declaration)
我想知道我在翻译语法时是否有任何错误，并且有什么改进措施可以让它更简化，同时遵循我所获得的语法。
编辑 2：已更新以包含新错误。
这是我正在解析的输入字符串：
int larger ( int first , int second ) {
if ( first > second ) {
return first ;
} else {
return second ;
}
}
void main ( void ) {
int count ;
int sum ;
int max ;
int x ;
x = input ( ) ;
max = x ;
sum = 0 ;
count = 0 ;
while ( x != 0 ) {
count = count + 1 ;
sum = sum + x ;
max = larger ( max , x ) ;
x = input ( ) ;
}
output ( count ) ;
output ( sum ) ;
output ( max ) ;
}
这是我从终端运行程序时收到的错误信息：
/Users/Joe/Documents/Eclipse Projects/Parser/src/pyparsing.py:1156: SyntaxWarning: null string passed to Literal; use Empty() instead
other = Literal( other )
/Users/Joe/Documents/Eclipse Projects/Parser/src/pyparsing.py:1258: SyntaxWarning: null string passed to Literal; use Empty() instead
other = Literal( other )
Expected ")" (at char 30), (line:6, col:26)
None