我正在尝试使用以下函数调整图像大小:
function resize_image($file, $w, $h, $crop=FALSE) {
list($width, $height) = getimagesize($file);
$r = $width / $height;
if ($crop) {
if ($width > $height) {
$width = ceil($width-($width*abs($r-$w/$h)));
} else {
$height = ceil($height-($height*abs($r-$w/$h)));
}
$newwidth = $w;
$newheight = $h;
} else {
if ($w/$h > $r) {
$newwidth = $h*$r;
$newheight = $h;
} else {
$newheight = $w/$r;
$newwidth = $w;
}
}
$src = imagecreatefromjpeg($file);
$dst = imagecreatetruecolor($newwidth, $newheight);
imagecopyresampled($dst, $src, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
return $dst;
}
创建函数后,我尝试使用以下代码显示调整大小后的图像,但它无法正常工作:
<?php
$img = resize_image('../images/avatar/demo.jpg', 120, 120);
var_dump($img); //The result is: resource(6, gd)
?>
<img src="<?php echo $img;?>"/>
提示:包含该函数没有问题。