我正在以编程方式导航到返回application/json格式的站点。我似乎无法在HttpURLConnection中读取返回的json。我正在使用Jackson将JSON demarshall到java对象中。代码如下:
InputStreamReader isr = new InputStreamReader(connection.getInputStream());
BufferedReader br = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
line = br.readLine();
}
geoLocation = (new ObjectMapper()).readValue(sb.toString(), GeoLocation.class);
当我打印sb.toString()时,我得到了奇怪的字符和Unicode编码。我应该得到一个格式良好的字符串。出现的异常为:
org.codehaus.jackson.JsonParseException: Illegal character ((CTRL-CHAR, code 31)): only regular white space (\r, \n, \t) is allowed between tokens
at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@3f6dadf9; line: 1, column: 2]
at org.codehaus.jackson.JsonParser._constructError(JsonParser.java:1291)
at org.codehaus.jackson.impl.JsonParserMinimalBase._reportError(JsonParserMinimalBase.java:385)
例如,如果我的网址是:
http://api.ipinfodb.com/v3/ip-city/?key=<mykeyhere>&ip=38.111.145.101&format=xml
我在浏览器窗口内看到以下内容:
<?xml version="1.0" encoding="UTF-8"?>
<Response>
<statusCode>OK</statusCode>
<statusMessage></statusMessage>
<ipAddress>38.111.145.101</ipAddress>
<countryCode>US</countryCode>
<countryName>UNITED STATES</countryName>
<regionName>CALIFORNIA</regionName>
<cityName>OAKLAND</cityName>
<zipCode>94601</zipCode>
<latitude>37.7993</latitude>
<longitude>-122.24</longitude>
<timeZone>-08:00</timeZone>
</Response>
但是当我这么做时
http://api.ipinfodb.com/v3/ip-city/?key=<mykeyhere>&ip=38.111.145.101&format=json
它会提示我下载一个文件。一旦文件下载完成并打开后,它包含以下内容:
{
"statusCode" : "OK",
"statusMessage" : "",
"ipAddress" : "38.111.145.101",
"countryCode" : "US",
"countryName" : "UNITED STATES",
"regionName" : "CALIFORNIA",
"cityName" : "OAKLAND",
"zipCode" : "94601",
"latitude" : "37.7993",
"longitude" : "-122.24",
"timeZone" : "-08:00"
}
我还尝试直接将输入流传递给jackson,但结果相同而失败。
geoLocation = (new ObjectMapper()).readValue(urlConn.getInputStream(), GeoLocation.class);
任何想法如何以可视化字符串格式从URLConn中检索JSON,以便我可以将其传递给Jacson?谢谢。