代码:
DECLARE @T1 TABLE ([ID] INT, [WD] DATE, [SD] DATETIME, [ED] DATETIME, [Val] INT)
INSERT INTO @T1 ( [ID], [WD], [SD], [ED], [VAL] )
VALUES ( 1, '2016-02-14', '2016-02-14 08:00:00', '2016-02-14 16:30:00', 12 )
,( 1, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 15 )
,( 3, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 12 )
,( 1, '2016-02-21', '2016-02-22 08:00:00', '2016-02-22 16:30:00', 100 )
,( 2, '2016-02-21', '2016-02-25 08:00:00', '2016-02-25 16:30:00', 124 )
,( 3, '2016-03-20', '2016-03-21 08:00:00', '2016-03-21 16:30:00', 10 )
,( 3, '2016-04-17', '2016-04-17 08:00:00', '2016-04-17 16:30:00', 8 );
DECLARE @StartDate DATE
, @EndDate DATE;
SELECT @StartDate = MIN(WD) FROM @T1
SELECT @EndDate = DATEADD(DAY,6,MAX(WD)) FROM @T1;
DECLARE @T2 TABLE (D DATE) -- Table generated to get ALL dates between the minium WD (Min Sunday) and 6 days after the maximum WD (Max Sunday + 6 days to complete the week date range)
INSERT INTO @T2 ( [D] )
SELECT DATEADD(DAY, NBR - 1, @StartDate)
FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS NBR
FROM sys.columns c
) NBR
WHERE NBR - 1 <= DATEDIFF(DAY, @StartDate, @EndDate);
SELECT * FROM @T1;
SELECT * FROM @T2;
描述:
@T1是一个预设的数据表,其中包含特定日期, [ID]是某种标识字段,[WD]表示不同的一周开始时间(星期日),[SD]表示在该[WD]周内的某天的开始时间,[ED]表示在该[WD]周内的某天的结束时间,[Val]为该ID / WD / SD / ED记录分配的某个值
@T2是我定义和填充的表,以获得MIN([WD])和MAX([WD])+6天之内的所有日期(以完成本周)
目标:
返回@T1数据以及那些[ID]/[WD]周缺失的任何日期。(请参考期望输出以更好地理解)
期望结果(从Excel复制,因此格式不同,但没关系)
[ID][WD] [SD] [ED] [Val]
1 2/14/2016 2/14/16 8:00 2/14/16 16:30 12
1 2/14/2016 2/15/16 00:00 2/15/16 00:00 NULL
1 2/14/2016 2/16/16 8:00 2/16/16 16:30 15
1 2/14/2016 2/17/16 00:00 2/17/16 00:00 NULL
1 2/14/2016 2/18/16 00:00 2/18/16 00:00 NULL
1 2/14/2016 2/19/16 00:00 2/19/16 00:00 NULL
1 2/14/2016 2/20/16 00:00 2/20/16 00:00 NULL
3 2/14/2016 2/14/16 00:00 2/14/16 00:00 NULL
3 2/14/2016 2/15/16 00:00 2/15/16 00:00 NULL
3 2/14/2016 2/16/16 8:00 2/16/16 16:30 12
3 2/14/2016 2/17/16 00:00 2/17/16 00:00 NULL
3 2/14/2016 2/18/16 00:00 2/18/16 00:00 NULL
3 2/14/2016 2/19/16 00:00 2/19/16 00:00 NULL
3 2/14/2016 2/20/16 00:00 2/20/16 00:00 NULL
1 2/21/2016 2/21/16 00:00 2/21/16 00:00 NULL
1 2/21/2016 2/22/16 8:00 2/22/16 16:30 100
1 2/21/2016 2/23/16 00:00 2/23/16 00:00 NULL
1 2/21/2016 2/24/16 00:00 2/24/16 00:00 NULL
1 2/21/2016 2/25/16 00:00 2/25/16 00:00 NULL
1 2/21/2016 2/26/16 00:00 2/26/16 00:00 NULL
1 2/21/2016 2/27/16 00:00 2/27/16 00:00 NULL
2 2/21/2016 2/21/16 00:00 2/21/16 00:00 NULL
2 2/21/2016 2/22/16 00:00 2/22/16 00:00 NULL
2 2/21/2016 2/23/16 00:00 2/23/16 00:00 NULL
2 2/21/2016 2/24/16 00:00 2/24/16 00:00 NULL
2 2/21/2016 2/25/16 8:00 2/25/16 16:30 124
2 2/21/2016 2/26/16 00:00 2/26/16 00:00 NULL
2 2/21/2016 2/27/16 00:00 2/27/16 00:00 NULL
3 3/20/2016 3/20/16 00:00 3/20/16 00:00 NULL
3 3/20/2016 3/21/16 8:00 3/21/16 16:30 10
3 3/20/2016 3/22/16 00:00 3/22/16 00:00 NULL
3 3/20/2016 3/23/16 00:00 3/23/16 00:00 NULL
3 3/20/2016 3/24/16 00:00 3/24/16 00:00 NULL
3 3/20/2016 3/25/16 00:00 3/25/16 00:00 NULL
3 3/20/2016 3/26/16 00:00 3/26/16 00:00 NULL
3 4/17/2016 4/17/16 8:00 4/17/16 16:30 8
3 4/17/2016 4/18/16 00:00 4/18/16 00:00 NULL
3 4/17/2016 4/19/16 00:00 4/19/16 00:00 NULL
3 4/17/2016 4/20/16 00:00 4/20/16 00:00 NULL
3 4/17/2016 4/21/16 00:00 4/21/16 00:00 NULL
3 4/17/2016 4/22/16 00:00 4/22/16 00:00 NULL
3 4/17/2016 4/23/16 00:00 4/23/16 00:00 NULL
我尝试使用交叉连接等技术,但无法获得所需的输出。