我需要知道如何在一个页面上触发多个Facebook像素,因为我们有多个广告正在运行。
我获取了每个像素的代码,并将其放置在页面上,然后我们有一个购物车页面,在其中触发或添加“购买”事件。但由于我已经将脚本复制了3次,它似乎会触发3次。我希望它只能针对每个像素触发一次。
这是我目前所拥有的:
<!-- Facebook Pixel Code - Ad 1-->
<script>
!function(f,b,e,v,n,t,s){if(f.fbq)return;n=f.fbq=function(){n.callMethod?
n.callMethod.apply(n,arguments):n.queue.push(arguments)};if(!f._fbq)f._fbq=n;
n.push=n;n.loaded=!0;n.version='2.0';n.queue=[];t=b.createElement(e);t.async=!0;
t.src=v;s=b.getElementsByTagName(e)[0];s.parentNode.insertBefore(t,s)}(window,
document,'script','//connect.facebook.net/en_US/fbevents.js');
fbq('init', 'xxxxxxxxxxxxx12');
fbq('track', "PageView");
// Purchase
// Track purchases or checkout flow completions (ex. landing on "Thank You" or confirmation page)
fbq('track', 'Purchase', {value: '1.00', currency: 'USD'});
</script>
<noscript><img height="1" width="1" style="display:none"
src="https://www.facebook.com/tr?id=xxxxxxxxxxxxx12&ev=PageView&noscript=1"
/></noscript>
<!-- End Facebook Pixel Code -->
<!-- Facebook Pixel Code - Ad 2-->
<script>
!function(f,b,e,v,n,t,s){if(f.fbq)return;n=f.fbq=function(){n.callMethod?
n.callMethod.apply(n,arguments):n.queue.push(arguments)};if(!f._fbq)f._fbq=n;
n.push=n;n.loaded=!0;n.version='2.0';n.queue=[];t=b.createElement(e);t.async=!0;
t.src=v;s=b.getElementsByTagName(e)[0];s.parentNode.insertBefore(t,s)}(window,
document,'script','//connect.facebook.net/en_US/fbevents.js');
fbq('init', 'xxxxxxxxxxxxx34');
fbq('track', "PageView");
// Purchase
// Track purchases or checkout flow completions (ex. landing on "Thank You" or confirmation page)
fbq('track', 'Purchase', {value: '1.00', currency: 'USD'});
</script>
<noscript><img height="1" width="1" style="display:none"
src="https://www.facebook.com/tr?id=xxxxxxxxxxxxx34&ev=PageView&noscript=1"
/></noscript>
<!-- End Facebook Pixel Code -->
<!-- Facebook Pixel Code - Ad 2-->
<script>
!function(f,b,e,v,n,t,s){if(f.fbq)return;n=f.fbq=function(){n.callMethod?
n.callMethod.apply(n,arguments):n.queue.push(arguments)};if(!f._fbq)f._fbq=n;
n.push=n;n.loaded=!0;n.version='2.0';n.queue=[];t=b.createElement(e);t.async=!0;
t.src=v;s=b.getElementsByTagName(e)[0];s.parentNode.insertBefore(t,s)}(window,
document,'script','//connect.facebook.net/en_US/fbevents.js');
fbq('init', 'xxxxxxxxxxxxx56');
fbq('track', "PageView");
// Purchase
// Track purchases or checkout flow completions (ex. landing on "Thank You" or confirmation page)
fbq('track', 'Purchase', {value: '1.00', currency: 'USD'});
</script>
<noscript><img height="1" width="1" style="display:none"
src="https://www.facebook.com/tr?id=xxxxxxxxxxxxx56&ev=PageView&noscript=1"
/></noscript>
<!-- End Facebook Pixel Code -->
这样做对吗?还是我需要采取不同的方法,以使购买事件不会触发4次。我正在使用Chrome的FB Pixel Helper插件来确保所有像素都能正常运行,但是我收到了多次触发的错误。
我应该这样做吗?
<!-- Facebook Pixel Code - ALL ADS-->
<script>
!function(f,b,e,v,n,t,s){if(f.fbq)return;n=f.fbq=function(){n.callMethod?
n.callMethod.apply(n,arguments):n.queue.push(arguments)};if(!f._fbq)f._fbq=n;
n.push=n;n.loaded=!0;n.version='2.0';n.queue=[];t=b.createElement(e);t.async=!0;
t.src=v;s=b.getElementsByTagName(e)[0];s.parentNode.insertBefore(t,s)}(window,
document,'script','//connect.facebook.net/en_US/fbevents.js');
fbq('init', 'xxxxxxxxxxxxx12');
fbq('init', 'xxxxxxxxxxxxx34');
fbq('init', 'xxxxxxxxxxxxx56');
fbq('track', "PageView");
// Purchase
// Track purchases or checkout flow completions (ex. landing on "Thank You" or confirmation page)
fbq('track', 'Purchase', {value: '1.00', currency: 'USD'});
</script>
<noscript><img height="1" width="1" style="display:none"
src="https://www.facebook.com/tr?id=xxxxxxxxxxxxx12&ev=PageView&noscript=1"
/></noscript>
<!-- End Facebook Pixel Code -->