我没有找到类似的帖子,所以希望这不是重复的问题。
我有一个C#类库,在Visual Studio 2012中尝试运行单元测试。我已经向我的解决方案添加了一个新的单元测试项目,并在其中添加了我的主要项目作为参考。我将我的单元测试项目设置为启动项目。当我尝试进行调试时,会出现错误信息:
类库输出类型的项目不能直接启动。
为了调试此项目,请将可执行项目添加到该解决方案中,并引用库项目。将可执行项目设置为启动项目。
根据msdn上的演练,当我点击“调试”时,应该正在运行测试。有什么想法吗?下面是我的单元测试代码:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using Common;
using Messages;
namespace MessageUnitTests
{
[TestClass]
class RegistrationTester
{
[TestMethod]
public void RegistrationRequest_TestConstructorsAndFactories()
{
RegistrationRequest rr1 = new RegistrationRequest("myhandle");
Assert.AreEqual("myhandle", rr1.Handle);
rr1 = new RegistrationRequest("longHandle-ABCDEFGHIJKLMNOPQRSTUVWXYZ-0123456789'|;:',.=-_+!@#$%^&*()");
Assert.AreEqual("longHandle-ABCDEFGHIJKLMNOPQRSTUVWXYZ-0123456789'|;:',.=-_+!@#$%^&*()", rr1.Handle);
rr1 = new RegistrationRequest("");
Assert.AreEqual("", rr1.Handle);
rr1 = new RegistrationRequest(null);
Assert.AreEqual(null, rr1.Handle);
rr1 = new RegistrationRequest("myhandle");
ByteList bytes = new ByteList();
rr1.Encode(bytes);
RegistrationRequest rr2 = RegistrationRequest.Create(bytes);
Assert.IsNotNull(rr2);
Assert.AreEqual(rr1.IsARequest, rr2.IsARequest);
Assert.AreEqual(rr1.MessageNr.ProcessId, rr2.MessageNr.ProcessId);
Assert.AreEqual(rr1.MessageNr.SeqNumber, rr2.MessageNr.SeqNumber);
Assert.AreEqual(rr1.ConversationId.ProcessId, rr2.ConversationId.ProcessId);
Assert.AreEqual(rr1.ConversationId.SeqNumber, rr2.ConversationId.SeqNumber);
Assert.AreEqual(rr1.RequestType, rr2.RequestType);
Assert.AreEqual(rr1.SessionId, rr1.SessionId);
Assert.AreEqual(rr1.Handle, rr2.Handle);
}
//[TestMethod]
//public void RegistrationRequest_EncodingDecoding()
//{
// Message m1 = new RegistrationRequest("myhandle");
// m1.MessageNr = MessageNumber.Create(10, 14);
// m1.ConversationId = MessageNumber.Create(10, 12);
// ByteList bytes = new ByteList
//}
}
}