6个回答
6
在你提供的文档中有写。
不是BlobService，而是BlobClient类。
from azure.storage.blob import BlobClient
blob_client = BlobClient.from_connection_string(
conn_str='my_conn_str',
container_name='my_container_name',
blob_name='my_blob_name')
with open("./SampleSource.txt", "rb") as data:
blob.upload_blob(data)
查看BlobClient.from_connection_string文档。
- Adam Marczak
4
这是我的示例代码，对我来说运行良好。
import os
from azure.storage.blob import BlockBlobService
root_path = '<your root path>'
dir_name = 'images'
path = f"{root_path}/{dir_name}"
file_names = os.listdir(path)
account_name = '<your account name>'
account_key = '<your account key>'
container_name = '<your container name, such as `test` for me>'
block_blob_service = BlockBlobService(
account_name=account_name,
account_key=account_key
)
for file_name in file_names:
blob_name = f"{dir_name}/{file_name}"
file_path = f"{path}/{file_name}"
block_blob_service.create_blob_from_path(container_name, blob_name, file_path)
以下是从 Azure Storage Explorer 截屏的结果，如下图所示。
更新：我使用的Python版本是Windows上的Python 3.7.4，并且所需的软件包是
azure-storage==0.36.0，您可以在https://pypi.org/project/azure-storage/中找到它。
$ virtualenv test$ cd test$ Scripts\active$ pip install azure-storage
然后，在当前Python虚拟环境中通过python upload_images.py运行我的示例代码。
- Peter Pan
2
1
目前有两个版本的azure.storage.blob。如果您创建一个Azure VM并在其中处理数据，则可能会得到其中之一。
较旧的版本需要（如Adam Marczak所指出的）：
from azure.storage.blob import BlobClient
blob = BlobClient.from_connection_string("my_connection_string", container="mycontainer", blob="my_blob")
with open("./SampleSource.txt", "rb") as data:
blob.upload_blob(data)
当新版本：
from azure.storage.blob import BlockBlobService
blob_service = BlockBlobService(account_name, account_key)
blob_service.create_blob_from_path(
container_name, blob_name , full_file_path )
- LukasP
0
def upload_file(remote_path,local_path):
try:
blobService = BlockBlobService(account_name=SETTINGS.AZURE_ACCOUNT_NAME, account_key=SETTINGS.AZURE_ACCOUNT_KEY)
blobService.create_blob_from_path('data',remote_path,local_path)
except Exception as e:
logger.error(f'Unable to save azure blob data. {str(e)}')
raise Exception(f'Unable to save azure blob data. {str(e)}')
- Abdul Rafay
0
from azure.storage.blob import BlobClient,ContentSettings
blob = BlobClient.from_connection_string(conn_str=connection_string, container_name=container_name, blob_name="my_blob9")
image_content_setting = ContentSettings(content_type='image/jpeg')
with open("/content/sample_data/kanha.png","rb") as data:
blob.upload_blob(data,overwrite=True,content_settings=image_content_setting)
- Kalpataru sahoo
1
如果您想上传PNG / JPEG / 原始文件，则可以使用此代码进行上传，否则对于二进制文件，您可以检查
https://github.com/Azure/azure-sdk-for-python/tree/main/sdk/storage/azure-storage-blob#create-a-container。 - Kalpataru sahoo0
显然，在最新的Python SDK中，create_blob_from_bytes和BlockBlobService都不存在[1]，除非您正在管理各种软件包的版本，否则默认情况下会获取它们。
我假设您可能想将其作为独立脚本执行。因此，您可以使用AzureCliCredential[2]进行身份验证，并通过SDK提供的方法检索必要的资源端点。
以下代码在Azure函数中无法工作。
from azure.storage.blob import (
BlobServiceClient,
ContentSettings
)
storage_connection_string='DefaultEndpointsProtocol=https;AccountName=<STORAGE_ACCOUNT_NAME>;AccountKey=<ACCOUNT_KEY>;EndpointSuffix=core.windows.net'
container_name =
blob_service_client = BlobServiceClient.(
conn_str=storage_connection_string
)
logging.debug(f'getting client for container : {container_name}')
container_client =
blob_service_client.get_container_client(container=container_name)
blob_client = container_client.get_blob_client(blob_name)
if blob_client.exists():
blob_client.delete_blob()
blob_client =blob_service_client.get_blob_client(container=container_name,
blob=blob_name)
try:
with open(filename, "rb") as data:
blob.upload(data)
content_settings =ContentSettings(content_type='image/png')
logging.debug(f'setting the content type : {content_settings}')
except Exception as e:
logging.error(str(e))
- samtoddler
网页内容由stack overflow 提供, 点击上面的可以查看英文原文，
原文链接
原文链接
azure-blob-storage，该包中也没有BlockBlobService。 - enterMLazure-storage包。我已经更新了我的帖子。 - Peter Pan