如何在Lua中将字符编码转换为字符串字符？

Question

如何在Lua中将字符编码转换为字符串字符？

例如：

d = 48
-- this is what I want
str_d = "0"

- Aftershock

Answer 1

你正在寻找 string.char ：

string.char (···)

Receives zero or more integers. Returns a string with length equal to the number of arguments, in which each character has the internal numerical code equal to its corresponding argument.

Note that numerical codes are not necessarily portable across platforms.

针对您的例子：

local d = 48
local str_d = string.char(d) -- str_d == "0"

- user142162

Answer 2

对于ASCII字符，您可以使用string.char。

对于UTF-8字符串，您可以使用utf8.char(在Lua 5.3中引入)以获取其代码点的字符。

print(utf8.char(48))    -- 0
print(utf8.char(29790)) -- 瑞

- Yu Hao