有一个DLL库,我在其中创建了一个表单并放置了一个线程。
在DLL中,我有一个函数:
procedure ShowForm; stdcall;
var
Form1 : TFormSNVFL7;
begin
Form1 := TFormSNVFL7.Create(nil);
Form1.Show;
end;
我创建了一个表单并显示它。这里没有问题。 我向这个dll添加了一个线程。 我在表单上放置了一个计时器。几秒钟后,我创建了一个线程并运行它。一切都正常,但当我尝试更改表单的任何内容时,什么也不会发生。
在同步函数中,我尝试更改标签,但没有任何反应。
以下是文件:
DLL pas:
library uploader;
uses
SysUtils,
Classes,
Forms,
UploaderForm in 'UploaderForm.pas' {FormUploader},
ThreadUpload in 'ThreadUpload.pas';
{$R *.res}
procedure ShowForm; stdcall;
var
upForm: TFormUploader;
begin
upForm := TFormUploader.Create(nil);
upForm.Show;
end;
exports
ShowForm;
begin
end.
表格密码:
unit UploaderForm;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, acPNG, ExtCtrls, JvExExtCtrls, JvImage, JvExControls, JvLabel,
JvAnimatedImage, JvGIFCtrl, ComCtrls, JvExComCtrls, JvProgressBar, StdCtrls,
FileCtrl, JvDriveCtrls;
type
TFormUploader = class(TForm)
imgRunning: TJvImage;
imgReady: TJvImage;
imgUpdate: TJvImage;
JvLabel1: TJvLabel;
JvLabel2: TJvLabel;
imgConnect: TJvImage;
imgUpload: TJvImage;
imgCheck: TJvImage;
JvLabel3: TJvLabel;
JvLabel4: TJvLabel;
JvLabel5: TJvLabel;
JvLabel6: TJvLabel;
imgRun: TJvImage;
imgOK: TJvImage;
imgDone: TJvImage;
JvProgressBar1: TJvProgressBar;
JvLabel7: TJvLabel;
fileList: TJvFileListBox;
Timer1: TTimer;
procedure FormCreate(Sender: TObject);
procedure Timer1Timer(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;
var
FormUploader: TFormUploader;
implementation
{$R *.dfm}
Uses ThreadUpload;
procedure TFormUploader.FormCreate(Sender: TObject);
begin
imgUpdate.Picture := imgReady.Picture;
imgConnect.Picture := imgReady.Picture;
imgUpload.Picture := imgReady.Picture;
imgCheck.Picture := imgReady.Picture;
imgRun.Picture := imgReady.Picture;
imgOK.Picture := imgReady.Picture;
fileList.Directory := ExtractFilePath(Application.ExeName) + 'csvexport/';
end;
procedure TFormUploader.Timer1Timer(Sender: TObject);
var
UpThread: TThread;
begin
Timer1.Enabled := False;
UpThread := UploadThread.Create(true);
UpThread.Create;
UpThread.Resume;
end;
end.
线程通行证:
unit ThreadUpload;
interface
uses
Classes, UploaderForm;
type
UploadThread = class(TThread)
private
{ Private declarations }
protected
procedure Execute; override;
end;
implementation
{ UploadThread }
procedure UploadThread.Execute;
begin
With FormUploader do
begin
imgUpdate.Picture := imgRunning.Picture;
end;
end;
end.
我无法解决这个问题。