将FileSystemInfo数组保存到文件

Question

将FileSystemInfo数组保存到文件

7

我正在尝试保存一个FileInfo和DirectoryInfo对象的数组用作日志文件。目标是在某个时间点捕获目录（和子目录）的图像，以便以后进行比较。我目前正在使用这个类来存储信息：

public class myFSInfo
{
    public FileSystemInfo Dir;
    public string RelativePath;
    public string BaseDirectory;
    public myFSInfo(FileSystemInfo dir, string basedir)
    {
        Dir = dir;
        BaseDirectory = basedir;
        RelativePath = Dir.FullName.Substring(basedir.Length + (basedir.Last() == '\\' ? 1 : 2));
    }
    private myFSInfo() { }
    /// <summary>
    /// Copies a FileInfo or DirectoryInfo object to the specified path, creating folders and overwriting if necessary.
    /// </summary>
    /// <param name="path"></param>
    public void CopyTo(string path)
    {
        if (Dir is FileInfo)
        {
            var f = (FileInfo)Dir;
            Directory.CreateDirectory(path.Substring(0,path.LastIndexOf("\\")));
            f.CopyTo(path,true);
        }
        else if (Dir is DirectoryInfo) Directory.CreateDirectory(path);
    }
}

我尝试过使用XML和二进制对我的类进行序列化，但没有成功。我还尝试创建一个新的类，该类不包含实际的FileInfo，而只包含选定的属性：

public class myFSModInfo
{
    public Type Type;
    public string BaseDirectory;
    public string RelativePath;
    public string FullName;
    public DateTime DateModified;
    public DateTime DateCreated;
    public myFSModInfo(FileSystemInfo dir, string basedir)
    {
        Type = dir.GetType();
        BaseDirectory = basedir;
        RelativePath = dir.FullName.Substring(basedir.Length + (basedir.Last() == '\\' ? 1 : 2));
        FullName = dir.FullName;
        DateModified = dir.LastWriteTime;
        DateCreated = dir.CreationTime;
    }
    private myFSModInfo() { }
    /// <summary>
    /// Copies a FileInfo or DirectoryInfo object to the specified path, creating folders and overwriting if necessary.
    /// </summary>
    /// <param name="path"></param>
    public void CopyTo(string path)
    {
        if (Type == typeof(FileInfo))
        {
            Directory.CreateDirectory(path.Substring(0, path.LastIndexOf("\\")));
            File.Copy(FullName,path, true);
        }
        else if (Type == typeof(DirectoryInfo)) Directory.CreateDirectory(path);
    }
    public void Delete() 
    {
        if (Type == typeof(FileInfo)) File.Delete(FullName);
        else if (Type == typeof(DirectoryInfo)) Directory.Delete(FullName);
    }
}

我也没有成功地序列化这个。我可以列出我在尝试中遇到的各种错误，但最好先选择最好的方法。以下是我的序列化代码：

public void SaveLog(string savepath, string dirpath)
    {
        var dirf = new myFSModInfo[1][];
        string[] patharr = {dirpath}; 
        GetFSInfo(patharr, dirf);

        var mySerializer = new System.Xml.Serialization.XmlSerializer(typeof(myFSModInfo[]));
        var myWriter = new StreamWriter(savepath);
        mySerializer.Serialize(myWriter, dirf[0]);
        myWriter.Close();

        /*var bf = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();   
        FileStream fs = new FileStream(savepath, FileMode.Create, FileAccess.Write);   
        bf.Serialize(fs, dirf[0]);  */
    }

- Kalev Maricq

4

认为你只能序列化属性，而不能序列化变量。 - Chuck Savage

你能提供一些更具体的细节，说明你遇到了哪些问题吗？ - Octopoid

1

你是否将该类声明为可序列化的？[Serializable] - Sorceri

我已经编辑了您的标题，请查看“问题标题是否应包含“标签”？”，共识是“不应该”。 - John Saunders

谢谢John。Sorceri - 我没有在我发布的代码之外做任何事情。如果将其声明为Serializable可以解决我的问题，你能告诉我语法吗？Octopoid - 我遇到的大多数问题都是由于类没有包含0个参数构造函数而导致序列化器失败。我还遇到了Type被保护变量的问题。如果有特定的路线应该关注，我可以发布确切的错误消息。 - Kalev Maricq

1个回答

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- devmb · Accepted Answer

FileSystemInfo不可序列化，因为它不是简单类型。 FileInfo不可序列化，因为它没有空默认构造函数。

因此，如果您想保存该信息，必须使用简单类型构建自己的类，该类包装FileInfo或FileSystemInfo中的信息。

[Serializable]
public class MyFileInfo
{
    public string Name { get; set; }

    public long Length { get; set;}

    /// <summary>
    /// An empty ctor is needed for serialization.
    /// </summary>
    public MyFileInfo(){
    }

    /// <summary>
    /// Initializes a new instance of the <see cref="test.MyFileInfo"/> class.
    /// </summary>
    /// <param name="fileInfo">File info.</param>
    public MyFileInfo(string path)
    {
        FileInfo fileInfo = new FileInfo (path);
        this.Length = fileInfo.Length;
        this.Name = fileInfo.Name;
        // TODO: add and initilize other members
    }
}

用法示例：

List<MyFileInfo> list = new List<MyFileInfo> ();

foreach (string entry in Directory.GetFiles(@"c:\temp"))
{
    list.Add (new MyFileInfo (entry));
}

XmlSerializer xsSubmit = new XmlSerializer(typeof(List<MyFileInfo>));
StringWriter sww = new StringWriter();
XmlWriter writer = XmlWriter.Create(sww);
xsSubmit.Serialize(writer, list);

Console.WriteLine (sww.ToString());