我可以在bash shell中使用十进制数字:
linux$ A=67
如何在bash中将67打印为十六进制?
作为一个Bash程序:
#!/bin/bash
decimal1=31
printf -v result1 "%x" "$decimal1"
decimal2=33
printf -v result2 "%x" "$decimal2"
echo $result1 $decimal1
echo $result2 $decimal2
或者直接使用bash shell:
el@defiant ~ $ printf '%x\n' 26
1a
el@defiant ~ $ echo $((0xAA))
170
el@defiant ~ $
printf
is also part of coreutils
- printf '%x\n' $1
in a shell script does the job: /path/to/script 26
- Stuart Cardall