Android无法从onPostExecute更新TextView

Question

我无法在AsyncTask（MainActivity内部类）的onPostExecute中设置TextView中的文本。

public class MainActivity  extends Activity {
...
private TextView txt_msg;
...
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    txt_msg =  (TextView) findViewById(R.id.txt_msg);
    txt_msg.setText("ON create"); // <-- OK this works

    ...
    ...

    btn = (Button) findViewById(R.id.btn_associa);
    btn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
                    String url = "http://myurl.php?a=1&b=2&c=3";
                    MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);
                    dlTask.execute();
            }
        }
    });

    ...
    ...
    ...


    class SQLAsync extends AsyncTask<URL, Integer, String> {
     private String myurl = "";

        public SQLAsync(String _url) {
            super();
            myurl = _url;
        }

        @Override
        protected void onPreExecute() {
        //empty
        }

        @Override
        protected String doInBackground(URL... urls) {
            InputStream is = null;
            String result = "";
            JSONObject jArray = null;

            try {
                URL url = new URL(myurl);
                HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                conn.setRequestMethod("GET");
                int resp_code = conn.getResponseCode();
                is = new BufferedInputStream(conn.getInputStream());

            } catch (Exception e) {
                Log.e("tag", "Error in http connection " + e.toString());
            }

            try {
                BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while (reader.readLine() != null) {
                    line = reader.readLine();
                    sb.append(line + "\n");
                }
                is.close();
                result = sb.toString();


            } catch (Exception e) {
                Log.e("tag", "Error converting result " + e.toString());
            }
            return result;
        }

        protected void onProgressUpdate(Integer... progress) {
        //empty
        }

        @Override
        protected void onPostExecute(String s) {
            String result = s;
            Log.i("davide", "String post execute " + s.toString());

            if (txt_msg!=null) // <-- THIS IS NULL
                txt_msg.setText("MESSAGGIO DI SISTEMA"); 

                ...
                ...
                ...

        }
    }

}

我查看了其他类似问题的帖子，但它们在AsyncTask中定义了TextView，而在我的情况下，我不明白哪里出错了。

- user3854399

---

由于您没有初始化textview对象，所以它始终会返回null... 我认为在设置文本之前应该检查该字符串是否为空。 - Iamat8

Answer 1

你正在从新的 MainActivity 实例中创建一个新的 SQLAsync，而不是现有的实例。

更改为:

MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);

至：

SQLAsync dlTask = new SQLAsync(url);

- George Mulligan

---

为什么不直接写成：SQLAsync dlTask = new SQLAsync(url) 呢？ - user5156016

@JawadLeWywadi 他真的应该那样做，所以我会编辑答案，谢谢。 - George Mulligan

谢谢！这解决了我的问题。这个答案和Clairvoyant的回答都是正确的。很抱歉只能选择一个 :) - user3854399

Answer 2

代替

MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);

按照以下方式进行初始化：

SQLAsync dlTask = new SQLAsync(url);

- Pankaj