iOS Swift 应用在前台时如何接收推送通知

Question

以下是我用来在应用程序前台接收推送通知的代码：

@available(iOS 10.0, *)
func userNotificationCenter(center: UNUserNotificationCenter, willPresentNotification notification: UNNotification, withCompletionHandler completionHandler: (UNNotificationPresentationOptions) -> Void)
{
     completionHandler([UNNotificationPresentationOptions.Alert,UNNotificationPresentationOptions.Sound,UNNotificationPresentationOptions.Badge])
}

但我的问题是，我的通知包含 [NSObject : AnyObject] 值。如何像后台通知一样接收它？

- Kavin Kumar Arumugam

---

你想从通知对象中访问用户信息吗？ - PlusInfosys

@iOS_devloper 是的，先生。 - Kavin Kumar Arumugam

我正在使用 "notification.request.content.userInfo" 来获取数据。你可以在上面的方法中打印出来。 - Amanpreet

您可以使用 notification.request.content.userInfo。 - PlusInfosys

@iOS_devloper 如果解决了这个问题，你应该将其作为答案加入（如果你有更多细节，也可以添加一些）。干杯！ - AL.

@AL. 谢谢！已发布。 - PlusInfosys

Answer 1

请将以下代码添加到AppDelegate.swift文件中。

@available(iOS 10.0, *)
func userNotificationCenter(_ center: UNUserNotificationCenter, willPresent notification: UNNotification, withCompletionHandler completionHandler: @escaping (UNNotificationPresentationOptions) -> Void)
{
    completionHandler([UNNotificationPresentationOptions.alert,UNNotificationPresentationOptions.sound,UNNotificationPresentationOptions.badge])
}

- Kavin Kumar Arumugam

---

如何在iOS 8.0中编写此代码？@Kavin Kumar Arumugam - Dilip Tiwari

好的，它会在前台显示通知，对吗Kavin Kumar Arumugam？ - Dilip Tiwari

我在iOS 10中收到了，但在iOS 8中没有收到。@Kavin Kumar Arumugam - Dilip Tiwari

我们可以在群聊中交流吗，@kavin kumar arumugam。 - Dilip Tiwari

现在有点忙，晚上再看并更新你的代码 @DilipTiwari - Kavin Kumar Arumugam

Answer 2

除非用户打开推送通知，否则您的应用程序将无法运行任何代码。推送通知由操作系统处理，当应用程序处于非活动或后台状态时，您的应用程序无法对其进行控制。您应该查看https://developer.apple.com/library/content/documentation/Performance/Conceptual/EnergyGuide-iOS/OptimizeVoIP.html以优化VoIP。

- Sagar Rathode

Answer 3

 func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any]) {

   if (application.applicationState == 0) // active --- forground
    {
       // publish your notification message
    }

}

- Sofeda

Answer 4

UNNOtification有一个属性request(UNNotificationRequest)，您可以使用它来获取用户信息。

使用以下方法从UNNotification访问用户信息：

let userinfo =  notification.request.content.userInfo

- PlusInfosys

Answer 5

  func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void)
{
    debugPrint("Received when is visible... :): \(userInfo)")
    

    guard let aps = userInfo["aps"] as? [String: AnyObject] else {
        completionHandler(.failed)
        return
      }
    
    let alert:Dictionary<String,String> = aps["alert"] as! Dictionary<String,String>

    let title:String = alert["title"]!
    let msg:String   = alert["body"]!
    
  
    let refreshAlert = UIAlertController(title: title, message: msg, preferredStyle: UIAlertController.Style.alert)
    
    refreshAlert.addAction(UIAlertAction(title: "Ok", style: .default, handler: { (action: UIAlertAction!) in
         
        refreshAlert.dismiss(animated: true, completion: nil)
      
    }))


    UIApplication.shared.windows.first!.rootViewController?.present(refreshAlert, animated: true, completion: nil)
 
}

- Blazej Kita