在我的数据库中,日期格式为2012-04-09 04:02:53
、2012-04-09 04:04:51
、2012-04-08 04:04:51
等。我需要检索出具有当前日期的数据,即只需匹配2012-04-09'
。我该如何使用Hibernate Criteria实现?
使用Restrictions.between()生成一个where子句,其中日期列介于'2012-04-09 00:00:00'和'2012-04-09 23:59:59'之间。
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date fromDate = df.parse("2012-04-09 00:00:00");
Date toDate = df.parse("2012-04-09 23:59:59");
criteria.add(Restrictions.between("dateField", fromDate, toDate));
请注意,Criteria API 中使用的所有属性都是 Java 属性名称,而不是实际列名称。
更新:仅使用 JDK 获取当前日期的 fromDate 和 toDate。
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.HOUR_OF_DAY, 0);
calendar.set(Calendar.MINUTE, 0);
calendar.set(Calendar.SECOND, 0);
Date fromDate = calendar.getTime();
calendar.set(Calendar.HOUR_OF_DAY, 23);
calendar.set(Calendar.MINUTE, 59);
calendar.set(Calendar.SECOND, 59);
Date toDate = calendar.getTime();
criteria.add(Restrictions.between("dateField", fromDate, toDate));
criteria.add(Expression.eq("yourDate", aDate))
fromDate.setTime(new Date());
fromDate.set(Calendar.HOUR_OF_DAY, 0);
fromDate.set(Calendar.MINUTE, 0);
fromDate.set(Calendar.SECOND, 0);
fromDate.set(Calendar.MILLISECOND, 0);
这段代码非常危险... 如果日期切换到夏令时(例如06.04.1980),您将遇到以下异常!!!
java.lang.IllegalArgumentException: HOUR_OF_DAY: 0 -> 1day
HQL: from human pat where year(pat.birthdate) = :start_day and month(pat.birthdate) = :start_month and year(pat.birthdate) = :start_year ");
params.put("start_day", startDate.get(Calendar.DAY_OF_MONTH));
params.put("start_month", startDate.get(Calendar.MONTH) + 1);
params.put("start_year", startDate.get(Calendar.YEAR));
最简单的方法是获取所有日期在给定日期的开始和结束之间的记录:
WHERE date BETWEEN :from AND :to
在您的Java代码中计算from
和to
。
用于计算午夜:
import static org.apache.commons.lang.time.DateUtils.ceiling;
import static org.apache.commons.lang.time.DateUtils.truncate;
Date someDay = new Date();
Date from = truncate(someDay, Calendar.DAY_OF_MONTH);
Date to = new Date(ceiling(someDay, Calendar.DAY_OF_MONTH).getTime() - 1);
2012年4月9日00:00:00 CEST
)和结束时间(2012年4月9日23:59:59 CEST
)。 - Tomasz Nurkiewicz如何在Hibernate中实现已经说过了。您可以使用Java代码准备Timestamp
对象,例如以下方法:
Calendar cFrom = Calendar.getInstance();
cFrom.setTime(new Date()); /* today */
cFrom.set(Calendar.HOUR_OF_DAY, 0);
cFrom.set(Calendar.MINUTE, 0);
cFrom.set(Calendar.SECOND, 0);
cFrom.set(Calendar.MILLISECOND, 0);
Timestamp from = new Timestamp(cFrom.getTime().getTime());
Calendar cTo = Calendar.getInstance();
cTo.setTime(new Date()); /* today */
cTo.set(Calendar.HOUR_OF_DAY, 23);
cTo.set(Calendar.MINUTE, 59);
cTo.set(Calendar.SECOND, 59);
cTo.set(Calendar.MILLISECOND, 999);
Timestamp to = new Timestamp(cTo.getTime().getTime());
final String QUERY = ""
+ "SELECT tr "
+ "FROM Type tr "
+ "WHERE tr.timestamp >= :timestampFrom AND tr.timestamp <= :timestampTo";
Query query = entityManager.createQuery(QUERY);
query.setParameter("timestampFrom", from);
query.setParameter("timestampTo", to);
@SuppressWarnings("unchecked")
List<Type> ts = (List<Type>)query.getResultList();
Restrictions.between("dateColumn", midnight1, midnight2)
The following code will work
Calendar fromDate = Calendar.getInstance();
fromDate.setTime(new Date());
fromDate.set(Calendar.HOUR_OF_DAY, 0);
fromDate.set(Calendar.MINUTE, 0);
fromDate.set(Calendar.SECOND, 0);
fromDate.set(Calendar.MILLISECOND, 0);
Calendar toDate = Calendar.getInstance();
toDate.setTime(new Date());
toDate.set(Calendar.HOUR_OF_DAY, 23);
toDate.set(Calendar.MINUTE, 59);
toDate.set(Calendar.SECOND, 59);
toDate.set(Calendar.MILLISECOND, 999);
criteria.add(Restrictions.between("loadDate", fromDate.getTime(),
toDate.getTime()));
// Hibernate 4.3中的日期时间比较
Select c from Customer c where c.date<{d '2000-01-01'}
23:59:59
给你+1。 - OO7