在查看了许多示例后,我整合了一些加密/解密方法,利用Rfc2898DeriveBytes
获取密钥和初始化向量。我的担忧是接收到我的加密内容的一方必须能够解密它。由于我无法控制他们使用的语言(可能是Java、PHP、C等),我该如何确保他们能够像我在.NET中使用Rfc2898DeriveBytes
类一样派生出密钥和初始化向量(IV)?以下是我正在使用的加密和解密方法。
Public Shared Function EncryptText(ByVal plainText As String, ByVal password As String) As String
Dim aesCrypto As Rijndael = Nothing
Dim plainTextBytes As Byte()
plainTextBytes = Encoding.Default.GetBytes(plainText)
Dim rfc2898 As Rfc2898DeriveBytes
rfc2898 = New Rfc2898DeriveBytes(password, GenerateSalt(password))
aesCrypto = Rijndael.Create()
aesCrypto.Padding = PaddingMode.ISO10126
Dim tx As ICryptoTransform
tx = aesCrypto.CreateEncryptor(rfc2898.GetBytes(32), rfc2898.GetBytes(16))
Dim encryptedBytes As Byte()
encryptedBytes = tx.TransformFinalBlock(plainTextBytes, 0, plainTextBytes.Length)
Return Convert.ToBase64String(encryptedBytes)
End Function
Public Shared Function DecryptText(ByVal encryptedText As String, ByVal password As String) As String
Dim aesCrypto As Rijndael = Nothing
Dim encryptedTextBytes As Byte()
encryptedTextBytes = Convert.FromBase64String(encryptedText)
Dim rfc2898 As Rfc2898DeriveBytes
rfc2898 = New Rfc2898DeriveBytes(password, GenerateSalt(password))
aesCrypto = Rijndael.Create()
aesCrypto.Padding = PaddingMode.ISO10126
Dim tx As ICryptoTransform
tx = aesCrypto.CreateEncryptor(rfc2898.GetBytes(32), rfc2898.GetBytes(16))
Dim decryptedBytes As Byte()
decryptedBytes = tx.TransformFinalBlock(encryptedTextBytes, 0, encryptedTextBytes.Length)
Return Encoding.Default.GetString(decryptedBytes)
End Function