Java:使用基本身份验证从URL加载位图时出现FileNotFoundException

4

我知道这里有很多类似的问题,但是没有一个能帮到我 :(

在我的Android应用程序中,我正在尝试从URL获取Drawable / Bitmap,具体步骤如下:

public Bitmap loadBitmap(ISettings settings) {
    Bitmap bm = null;
    InputStream is = null;
    BufferedInputStream bis = null;

    final URL imageURL = new URL("http://domain.com/profile/image");
    final String authString = settings.getUserName() + ":" + settings.getPassword();
    final String authStringEnc = Base64.encodeToString(authString.getBytes(), Base64.DEFAULT);

    URLConnection conn = url.openConnection();
    conn.setRequestProperty("Authorization", "Basic " + authStringEnc);
    conn.connect();
    is = conn.getInputStream();
    bis = new BufferedInputStream(is, 8192);
    bm = BitmapFactory.decodeStream(bis);
    return bm;
}

但是,每次我启动这个程序,都会发生一些意想不到的事情:
java.io.FileNotFoundException: http://domain.com/profile/image

以下是该资源的curl命令,希望对您有所帮助:

curl -u Username:Password http://domain.com/profile/image

以及在Wireshark中的输出:

GET /profile/image HTTP/1.1
Authorization: Basic BASICAUTHSTRING
User-Agent: curl/7.25.0 (i386-pc-win32) libcurl/7.25.0 OpenSSL/0.9.8u zlib/1.2.6 libidn/1.18 libssh2/1.4.0 librtmp/2.3
Host: domain.com
Accept: */*

HTTP/1.1 200 OK
Date: Mon, 21 May 2012 18:36:11 GMT
Server: Apache/2.2.14 (Ubuntu)
Set-Cookie: JSESSIONID=65178AC10C59F372FEC901EBB71F38F7; Path=/profile
Content-Disposition: attachment; filename="profile.name.png"
Content-Length: 33195
Content-Type: image/png;charset=UTF-8

‰PNG
.. just the bytes of png which I cannot enter here as it would be too long :)

这个问题怎么解决?

编辑 #1:

从手机到网络的流量捕获,我看到了这个,这有点显而易见 :) - 但我不知道如何解决:

GET /profile/image HTTP/1.1
Authorization: Basic BASICAUTHSTRING
User-Agent: Dalvik/1.4.0 (Linux; U; Android 2.3.7; Nexus One Build/GRK39F)
Host: domain.com
Connection: Keep-Alive
Accept-Encoding: gzip

HTTP/1.1 400 Bad Request    
Date: Mon, 21 May 2012 23:01:42 GMT    
Server: Apache/2.2.14 (Ubuntu)    
Vary: Accept-Encoding
Content-Length: 327    
Connection: close    
Content-Type: text/html; charset=iso-8859-1   

<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>400 Bad Request</title>
</head><body>
<h1>Bad Request</h1>
<p>Your browser sent a request that this server could not understand.<br />
</p>
<hr>
<address>Apache/2.2.14 (Ubuntu) Server at domain.com Port 80</address>
</body></html>

编辑 #2:

这是什么巫术?使用curl并使用与设备上完全相同的头信息:

curl -H "Connection: Keep-Alive" -H "Accept-Encoding: gzip" -H "Accept:" -H "User-Agent: curl/7.25.0 (i386-pc-win32) libcurl/7.25.0 OpenSSL/0.9.8u zlib/1.2.6 libidn/1.18 libssh2/1.4.0 librtmp/2.3" -u Username:Password http://domain.com/profile/image

我立即了解了这个形象:< 这里发生了什么事?

1
当你使用Wireshark分析Java代码时会发生什么? - Jeremy Stein
我现在已经搞定了。明天会添加答案。 - Jonas Gröger
1个回答

6

最终我成功了。

我以为BASICAUTHSTRING是正确的 - 好吧,我错了一点。

android.util.Base64.encodeToString(authString.getBytes(), android.util.Base64.DEFAULT)

将在末尾添加一个新行。因此,请使用
android.util.Base64.No_WRAP

标志。

所以所有的麻烦实际上只是关于一个字节而已 :)


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