删除每隔一个逗号，并用括号括起来。

Question

使用jQuery，我有一串坐标字符串，如下所示：

38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976

我需要它们看起来像这样：

[38.313072, -89.863845] [38.312675, -89.863586] [38.310405, -89.862091] [38.310405,-89.862091] [38.309913, -89.861976] [38.309768, -89.861976] [38.309768, -89.861976] [38.30965, -89.861991]

我需要想办法将每隔一个逗号用空格和括号替换成坐标集。

有什么好的建议吗？

- Dean

Answer 1

你可以使用正则表达式。

([-\d.]+),([-\d.]+),?

正则表达式解释和实时演示

1. [-\d.]: 字符类，- 匹配连字符 -，\d 匹配一个数字，. 匹配句点 .。当在类序列中提到时，顺序无关紧要。
2. +: 匹配前面匹配项的一个或多个出现
3. (...): 捕获组。大括号内的匹配项被捕获并返回为 $1、$2 等。
4. ,?: 不匹配其他逗号
5. g: 全局匹配。匹配所有可能的出现。

jsFiddle 演示

var str = '38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976';

var result = str.replace(/([-\d.]+),([-\d.]+),?/g, '[$1, $2] ').trim();
document.getElementById('output').innerHTML = JSON.stringify(result, 0, 2);

<pre id="output"></pre>

- Tushar

---

非常接近，但我不需要方括号集合之间的逗号。 - Dean

@Tushar，你看，它不能被安全地移除！ - Anonymous0day

@Dean，请看下面我的回答！它完全符合你的需求！ - Anonymous0day

@Tushar好多了！以前不太安全！ - Anonymous0day

@Dean 欢迎！很高兴能帮助 :) - Tushar

@Tushar - 等一下...我确实需要那个逗号。 - Dean

Answer 2

使用正则表达式！它非常适合这个！

var str = "38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976,38.30965, -89.861991";

var expected = "[38.313072, -89.863845] [38.312675, -89.863586] [38.310405, -89.862091] [38.310405,-89.862091] [38.309913, -89.861976] [38.309768, -89.861976] [38.309768, -89.861976] [38.30965, -89.861991]"


var computed = str.replace(/(([0-9\-. ]*)(,)([0-9\-. ]*)),?/g, '[$2 $3 $4] ');

document.write('computed<br>')
document.write(str.replace(/(([0-9\-. ]*)(,)([0-9\-. ]*)),?/g, '[$2 $3 $4] '))



document.write( "<hr>expected<br>" + expected  )

- Anonymous0day

---

我再次阅读了问题，发现OP想要用空格替换每个逗号，输入字符串中不包含空格，因此可以删除类中的“-”空格。 - Tushar

@Tushar，我已经修改了我的答案，让你更容易看到它是如何“完美地契合”的！（我添加了预期和计算结果），这样你就可以进行比较 :-) - Anonymous0day

你仍然可以从字符类中删除空格，[0-9\-. ] ==> [0-9\-.] +1 - Tushar

可以，但最好保留它，因为我们可以匹配包含“空格”的人类输入！ - Anonymous0day

@Tushar 是的！当然可以！为什么不呢！ - Anonymous0day

Answer 3

这应该可以完成工作。

function toPairs(src){
  // Split the string into values.
  var values = src.split(',');
  
  // Group these values 2 by 2.
  var pairs = [];
  for(var i = 0; i < values.length; i += 2){
    pairs.push("[" + values[i] + ", " + values[i + 1] + "]");
  }
  
  // Join with a whitespace.
  return pairs.join(" ");
}

document.body.innerHTML = toPairs("38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976");

- Quentin Roy

Answer 4

尝试使用while循环，Array.prototype.splice()，将结果作为数组的数组返回。

var str = "38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976"
, res = []
, arr = str.split(",");
while (arr.length) res.push(arr.splice(0, 2))

console.log(res, JSON.stringify(res, null, 2))

- guest271314

---

你忘记在正则表达式中加入-减号了。 - Tushar

@Tushar 请查看更新的帖子。用 .splice() 替换了 while 循环和 RegExp。 - guest271314

Answer 5

不太美观，但它能工作：

var coordinateString = "38.313072,-89.863845,38.312675,-89.863586,38.310405,-89.862091,38.310405,-89.862091,38.309913,-89.861976,38.309768,-89.861976,38.309768,-89.861976";

var coordinateArray = coordinateString.split(",");
var coordinateResult = "";
var i = 0;
while(i<coordinateArray.length){
  coordinateResult +="[" + coordinateArray[i] + ", " + coordinateArray[i+1] + "]";
  i += 2;
}

- Tobias Delp