如何让LINQ to XML忽略所有命名空间?或者说,如何剥离命名空间?
我问这个问题是因为命名空间被以半随机的方式设置,而我已经厌倦了不得不同时搜索具有和不具有命名空间的节点。
改为:
nodes.Elements("Foo")
写:
nodes.Elements().Where(e => e.Name.LocalName == "Foo")
当你厌倦了它,可以自己编写扩展方法:
public static IEnumerable<XElement> ElementsAnyNS<T>(this IEnumerable<T> source, string localName)
where T : XContainer
{
return source.Elements().Where(e => e.Name.LocalName == localName);
}
/foo/bar | /foo/ns:bar | /ns:foo/bar | /ns:foo/ns:bar
local-name()
函数:/*[local-name() = 'foo']/*[local-name() = 'bar']
xDoc.Root.Descendants().Where(e => e.Name.LocalName == "SomeName");
- AaronLS这是一个去除命名空间的方法:
private static XElement StripNamespaces(XElement rootElement)
{
foreach (var element in rootElement.DescendantsAndSelf())
{
// update element name if a namespace is available
if (element.Name.Namespace != XNamespace.None)
{
element.Name = XNamespace.None.GetName(element.Name.LocalName);
}
// check if the element contains attributes with defined namespaces (ignore xml and empty namespaces)
bool hasDefinedNamespaces = element.Attributes().Any(attribute => attribute.IsNamespaceDeclaration ||
(attribute.Name.Namespace != XNamespace.None && attribute.Name.Namespace != XNamespace.Xml));
if (hasDefinedNamespaces)
{
// ignore attributes with a namespace declaration
// strip namespace from attributes with defined namespaces, ignore xml / empty namespaces
// xml namespace is ignored to retain the space preserve attribute
var attributes = element.Attributes()
.Where(attribute => !attribute.IsNamespaceDeclaration)
.Select(attribute =>
(attribute.Name.Namespace != XNamespace.None && attribute.Name.Namespace != XNamespace.Xml) ?
new XAttribute(XNamespace.None.GetName(attribute.Name.LocalName), attribute.Value) :
attribute
);
// replace with attributes result
element.ReplaceAttributes(attributes);
}
}
return rootElement;
}
使用示例:
XNamespace ns = "http://schemas.domain.com/orders";
XElement xml =
new XElement(ns + "order",
new XElement(ns + "customer", "Foo", new XAttribute("hello", "world")),
new XElement("purchases",
new XElement(ns + "purchase", "Unicycle", new XAttribute("price", "100.00")),
new XElement("purchase", "Bicycle"),
new XElement(ns + "purchase", "Tricycle",
new XAttribute("price", "300.00"),
new XAttribute(XNamespace.Xml.GetName("space"), "preserve")
)
)
);
Console.WriteLine(xml.Element("customer") == null);
Console.WriteLine(xml);
StripNamespaces(xml);
Console.WriteLine(xml);
Console.WriteLine(xml.Element("customer").Attribute("hello").Value);
我在搜索一个简单的方法来忽略属性命名空间时发现了这个问题,这里提供一个基于Pavel答案的扩展,用于在访问属性时忽略命名空间(为了更容易复制,我包含了他的扩展):
public static XAttribute AttributeAnyNS<T>(this T source, string localName)
where T : XElement
{
return source.Attributes().SingleOrDefault(e => e.Name.LocalName == localName);
}
public static IEnumerable<XElement> ElementsAnyNS<T>(this IEnumerable<T> source, string localName)
where T : XContainer
{
return source.Elements().Where(e => e.Name.LocalName == localName);
}