我正在尝试使用sequelize获取与模型“用户”相关的模型“评分”的平均评分。
我正在尝试使用sequelize获取与模型“用户”相关的模型“评分”的平均评分。
sequelize.sync({logging: false}).then(()=>{
return Model.Rating.findAll({
attributes: [[Sequelize.fn('avg', Sequelize.col('stars')),'rating']]
})
}).then(res => {
res = res.map(r => r.get())
console.log(res);
})
当我直接从“评分”模型尝试时,我得到了正确的响应:
[ { rating: '3.5000000000000000' } ]
然而,当尝试通过“用户”关联来执行相同操作时,我得到了分开的值,而不是平均值。
sequelize.sync({logging: false}).then(()=>{
return Model.User.findOne({
where: {id: 7},
include : [{
model: Model.Rating, as: 'seller_rating',
attributes: [[Sequelize.fn('avg', Sequelize.col('stars')),'rating']]
}],
attributes: {
exclude: ['password']
},
group: ['seller_rating.id', 'user.id'],
})
}).then(res => {
res = res.get()
res.seller_rating = res.seller_rating.map(r => r.get())
console.log(res)
})
否则sequelize会抛出错误,因此我不得不在组中添加“seller_rating.id”和“user.id”。
{
id: 7,
email: 'example@gmail.com',
createdAt: 2020-01-20T09:07:47.101Z,
updatedAt: 2020-01-21T08:58:52.036Z,
seller_rating: [
{ rating: '4.0000000000000000' },
{ rating: '3.0000000000000000' }
]
}
以下是用户和评分的模型 用户:
let User = sequelize.define('user', {
email: {type: Sequelize.STRING, unique: true, allowNull: false},
password : {type: Sequelize.STRING, },
})
评分:
let Rating = sequelize.define('rating', {
seller_id: {
type: Sequelize.INTEGER,
references: {model: User, key: 'id'},
unique: 'rateObject'
},
buyer_id: {
type: Sequelize.INTEGER,
references: {model: User, key: 'id'},
unique: 'rateObject'
},
stars: {
type: Sequelize.INTEGER,
validate: {
min: 1,
max: 5
},
allowNull: false
}
})
Rating.belongsTo(User,{ onDelete: 'cascade', foreignKey: 'seller_id'})
Rating.belongsTo(User,{ onDelete: 'cascade', foreignKey: 'buyer_id'})
User.hasMany(Rating, { foreignKey: 'seller_id', as: 'seller_rating'})
User.hasMany(Rating, { foreignKey: 'buyer_id', as: 'buyer_rating'})