如何获取光标位置像素的颜色?我知道如何使用MousePosition获取鼠标位置,但我无法弄清楚如何获取该位置处的像素颜色。
如何获取光标位置像素的颜色?我知道如何使用MousePosition获取鼠标位置,但我无法弄清楚如何获取该位置处的像素颜色。
一份C#版本:如何使用C#获取像素点X,Y的颜色?
在VB.NET中重写应该很容易。
快速简单但非常慢,但它可以工作。
这个想法是将屏幕复制到位图中,可以使用内置于drawing.graphics对象中的GDI+来完成。然后简单地读取生成的位图。获取像素非常缓慢。最好的方法是直接读取图像字节数组。
Function MakeScreenShot() As Drawing.Bitmap
Dim out As Drawing.Bitmap
'Get the screen Size
Dim bounds As Rectangle = Screen.GetBounds(Point.Empty)
'create the bitmap
out = New Drawing.Bitmap(bounds.Width, bounds.Height)
'create a graphic object to recive the pic
Using gr As Drawing.Graphics = Graphics.FromImage(out)
'Copy the screen using built in API
gr.CopyFromScreen(Point.Empty, Point.Empty, bounds.Size)
End Using
Return out
End Function
Private Sub Button5_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click
Dim BM As Drawing.Bitmap = MakeScreenShot()
Dim mouseloc As Point = Cursor.Position
Dim c As Color = BM.GetPixel(mouseloc.X, mouseloc.Y) ' The Slowest way possable to read a color
Debug.Print(c.R & "," & c.G & "," & c.B)
End Sub
享受吧。
尝试这段代码:
#Region "#include"
Imports System
Imports System.Drawing
Imports System.Runtime.InteropServices
#End Region
Public Class Test
#Region "From Windows API"
<DllImport("user32.dll", SetLastError:=True)> _
Public Shared Function GetWindowDC(ByVal hwnd As IntPtr) As IntPtr
'Do not try to name this method "GetDC" it will say that user32 doesnt have GetDC !!!
End Function
<DllImport("user32.dll", SetLastError:=True)> _
Public Shared Function ReleaseDC(ByVal hwnd As IntPtr, ByVal hdc As IntPtr) As Int32
End Function
<DllImport("gdi32.dll", SetLastError:=True)> _
Public Shared Function GetPixel(ByVal hdc As IntPtr, ByVal nXPos As Integer, ByVal nYPos As Integer) As UInteger
End Function
#End Region
REM --Test--
#Region "Some Functions"
Public Function GetPixelColor(ByVal x As Integer, ByVal y As Integer) As Color
Dim hdc As IntPtr = GetWindowDC(IntPtr.Zero)
Dim pixel As UInteger = GetPixel(hdc, x, y)
Dim color As Color
ReleaseDC(IntPtr.Zero, hdc)
MsgBox(pixel)
color = color.FromArgb(Int(pixel And &HFF), _
Int(pixel And &HFF00) >> 8, _
Int(pixel And &HFF0000) >> 16)
Return color
End Function
#End Region
REM --Test--
#Region "OnClick"
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim mouseloc As Point = Cursor.Position
Me.Label1.BackColor = GetPixelColor(mouseloc.X, mouseloc.Y)
Me.Refresh()
End Sub
#End Region
End Class
保持简单,不要过于优化但能完成任务:
Public Class Form1
Declare Auto Function FindWindow Lib "user32" (ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr
Declare Function GetDC Lib "user32" (ByVal hWnd As IntPtr) As IntPtr
Declare Function ReleaseDC Lib "user32" (ByVal hwnd As IntPtr, ByVal hdc As IntPtr) As IntPtr
Private Declare Function GetPixel Lib "gdi32" (ByVal hdc As IntPtr, ByVal X As Int32, ByVal Y As Int32) As Int32
Private Function CheckScreen()
Dim CursorLoc As Point = Cursor.Position
Dim hDC As IntPtr = GetDC(0) '0 = Get the color to any window on screen, not only your app
Try
Dim CursorColor As Integer = GetPixel(hDC, CursorLoc.X, CursorLoc.Y)
Me.Panel1.BackColor = ColorTranslator.FromWin32(CursorColor) 'a simple panel to show the color
Me.Refresh()
Return True
Catch ex As Exception
Return False
Finally
ReleaseDC(0, hDC)
End Try
End Function
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
Me.Timer1.Start() 'Timer with a short delay
End Sub
Private Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick
CheckScreen()
End Sub
End Class
这实际上比你想象的要难。我建议寻找一些已经完成此操作的示例代码,并复制它们的技术。
最终,算法将需要执行以下操作:
听起来很简单,但并不容易。