避免硬编码,尝试使代码具有动态性。以下是代码,它适用于任何xml。我已经使用了SAX解析器,您可以使用dom、xpath,这取决于您。我将所有标签名称和值存储在map中,之后检索任何想要的值变得容易。希望这有所帮助。
示例XML:
<parent>
<child >
<child1> value 1 </child1>
<child2> value 2 </child2>
<child3> value 3 </child3>
</child>
<child >
<child4> value 4 </child4>
<child5> value 5</child5>
<child6> value 6 </child6>
</child>
</parent>
JAVA CODE:
import java.io.File;
import java.io.IOException;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class saxParser {
static Map<String,String> tmpAtrb=null;
static Map<String,String> xmlVal= new LinkedHashMap<String, String>();
public static void main(String[] args) throws ParserConfigurationException, SAXException, IOException, VerifyError {
SAXParserFactory saxDoc = SAXParserFactory.newInstance();
SAXParser saxParser = saxDoc.newSAXParser();
DefaultHandler handler = new DefaultHandler() {
String tmpElementName = null;
String tmpElementValue = null;
@Override
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
tmpElementValue = "";
tmpElementName = qName;
tmpAtrb=new HashMap();
for (int i=0; i<attributes.getLength(); i++) {
String aname = attributes.getLocalName(i);
String value = attributes.getValue(i);
tmpAtrb.put(aname, value);
}
}
@Override
public void endElement(String uri, String localName, String qName)
throws SAXException {
if(tmpElementName.equals(qName)){
System.out.println("Element Name :"+tmpElementName);
for (Map.Entry<String, String> entrySet : tmpAtrb.entrySet()) {
System.out.println("Attribute Name :"+ entrySet.getKey() + "Attribute Value :"+ entrySet.getValue());
}
System.out.println("Element Value :"+tmpElementValue);
xmlVal.put(tmpElementName, tmpElementValue);
System.out.println(xmlVal);
String getKeyValues=xmlVal.get(tmpElementName);
System.out.println("XmlTag:"+tmpElementName+":::::"+"ValueFetchedFromTheMap:"+getKeyValues);
}
}
@Override
public void characters(char ch[], int start, int length) throws SAXException {
tmpElementValue = new String(ch, start, length) ;
}
};
saxParser.parse(new File("D:/Test _ XML/file.xml"), handler);
}
}
OUTPUT:
Element Name :child1
Element Value : value 1
XmlTag:<child1>:::::ValueFetchedFromTheMap: value 1
Element Name :child2
Element Value : value 2
XmlTag:<child2>:::::ValueFetchedFromTheMap: value 2
Element Name :child3
Element Value : value 3
XmlTag:<child3>:::::ValueFetchedFromTheMap: value 3
Element Name :child4
Element Value : value 4
XmlTag:<child4>:::::ValueFetchedFromTheMap: value 4
Element Name :child5
Element Value : value 5
XmlTag:<child5>:::::ValueFetchedFromTheMap: value 5
Element Name :child6
Element Value : value 6
XmlTag:<child6>:::::ValueFetchedFromTheMap: value 6
Values Inside The Map:{child1= value 1 , child2= value 2 , child3= value 3 , child4= value 4 , child5= value 5, child6= value 6 }