好的，所以我生成了一个CTE，其中包含考虑范围内所有日期的日期。
对于这些日期中的每一个，我生成了FLAG=1，表示我认为检测到了重叠。
然后我使用row_number()作为“岛屿”问题的标准解决方案，并输出flag=1的“岛屿”的开始和结束时间。
希望有帮助，我得到了您对13570的结果，但是根据我的理解，“重叠”应该是整个13579都重叠。也许需要进一步解释和调整。如果您能够按照您的规则生成FLAG，则排名部分仍将适用。
CREATE TABLE #EventsTBL
(
PID INT,
EID INT,
StartDate DATETIME,
EndDate DATETIME
);
INSERT INTO #EventsTBL
VALUES
(13579, '1', '01 Jan 2018', '31 Mar 2019'),
(13579, '2', '01 Feb 2018', '31 May 2018'),
(13579, '2', '01 Jul 2018', '31 Jan 2019'),
(13579, '7', '01 Mar 2018', '31 Mar 2019'),
(13579, '5', '01 Feb 2018', '30 Apr 2018'),
(13579, '5', '01 Oct 2018', '31 Mar 2019'),
(13579, '8', '01 Jan 2018', '30 Apr 2018'),
(13579, '8', '01 Jun 2018', '31 Dec 2018'),
(13579, '13', '01 Jan 2018', '31 Mar 2019'),
(13579, '6', '01 Apr 2018', '31 May 2018'),
(13579, '6', '01 Sep 2018', '30 Nov 2018'),
(13579, '4', '01 Feb 2018', '31 Jan 2019'),
(13579, '19', '01 Mar 2018', '31 Jul 2018'),
(13579, '19', '01 Oct 2018', '28 Feb 2019'),
(13570, '16', '01 Feb 2018', '30 Jun 2018'),
(13570, '16', '01 Aug 2018', '31 Aug 2018'),
(13570, '16', '01 Oct 2018', '28 Feb 2019'),
(13570, '23', '01 Mar 2018', '30 Jun 2018'),
(13570, '23', '01 Nov 2018', '31 Jan 2019');
SELECT count(enddate) FROM (SELECT CAST('19660423' as date) dt) A LEFT JOIN #EventsTBL B ON A.dt = b.StartDate;
WITH MIN_MAX AS (SELECT MIN(StartDate) S , MAX(EndDate) E FROM #EventsTBL ),
ALL_DATES AS (SELECT S DT FROM MIN_MAX
UNION ALL
SELECT DATEADD(day,1,DT) FROM ALL_DATES WHERE DT < (SELECT E FROM MIN_MAX)
),
BuildFlags AS (SELECT P.pid,
DT,
COUNT(e.PID ) CNT,
CASE WHEN COUNT(e.pid) > 1 THEN 1 ELSE 0 END FLAG,
row_number() OVER(partition by p.pid order by DT) RN
FROM ALL_DATES A CROSS JOIN (SELECT DISTINCT E2.pid FROM #EventsTBL E2) P
LEFT JOIN
#EventsTBL E ON P.PID = E.pid AND
A.DT BETWEEN E.StartDate AND E.EndDate GROUP BY P.pid,DT),
AddRanks AS (SELECT *,rn - row_number()over(partition by pid,flag order by dt) groupRank FROM BuildFlags)
select pid,min(dt) as start, max(dt) as ending from AddRanks
where flag = 1
group by pid,grouprank
order by pid,min(dt)
option(maxrecursion 0)
编辑 - 我想我明白你的意思了，你想将pid和eid合并成唯一的pid和eid，并使用存在的日期。然后，您将所有pid和eid同时处于活动状态定义为重叠。因此，我提出了以下修改。
;WITH MIN_MAX AS (SELECT MIN(StartDate) S , MAX(EndDate) E FROM #EventsTBL ),
ALL_DATES AS (SELECT S DT FROM MIN_MAX
UNION ALL
SELECT DATEADD(day,1,DT) FROM ALL_DATES WHERE DT < (SELECT E FROM MIN_MAX)
),
GROUPED AS (SELECT Q.pid,Q.eid,q.dt,case when max(tx.pid) is null then 0 else 1 end YES from (Select * FROM All_Dates cross join (select distinct pid,eid from #EventsTBL) AQ) Q
LEFT JOIN #EventsTBL TX ON TX.PID = Q.pid and tx.EID = Q.eid and
Q.DT BETWEEN TX.StartDate AND TX.EndDate GROUP BY q.pid,q.eid,q.dt
),
BuildFlags AS (SELECT g.pid,g.dt, row_number() OVER(partition by g.pid order by g.DT) RN,
CASE WHEN WQ.tot = (SELECT count(distinct g2.eid) FROM grouped g2 WHERE g2.PID = G.pid and g2.dt=g.dt and g2.yes=1) then 1 else 0 end FLAG
FROM GROUPED G cross apply (select count(distinct E9.eid) tot FROM #EventsTBL E9 WHERE E9.PID = G.pid) WQ)
,AddRanks AS (SELECT *,rn - row_number()over(partition by pid,flag order by dt) groupRank FROM BuildFlags)
select pid,min(dt) as start, max(dt) as ending from AddRanks
where flag = 1
group by pid,grouprank
order by pid,min(dt)
option(maxrecursion 0);
。