使用HttpUrlConnection向服务器发送POST请求

Question

使用HttpUrlConnection向服务器发送POST请求

androidposthttp-posthttpurlconnectionhttp-response-codes

3

我被卡住了。我想使用HttpUrlConnection实现POST方法，将电子邮件、姓名和密码发布到服务器以注册用户。以下是我的代码：

public void createNewProfile(View view){

    new Post().execute("http://myurl.com");

}

private class Post extends AsyncTask<String, Void, String>{

    @Override
    protected String doInBackground(String... params) {

        try {

            URL url = new URL("http://myurl.com");
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();

            conn.setRequestMethod("POST");
            conn.setDoInput(true);
            conn.setDoOutput(true);

            ContentValues values = new ContentValues();
            values.put("email", "abc@xyz.com");
            values.put("password", 123);
            values.put("name","ABC");

            OutputStream os = conn.getOutputStream();
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(os, "UTF-8"));
            writer.write(getQuery(values));
            writer.flush();
            writer.close();
            os.close();
            response = conn.getResponseCode();
            conn.connect();

        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            Log.i("Result",String.valueOf(e));
        }
        return null;
    }

    private String getQuery(ContentValues values) throws UnsupportedEncodingException
    {
        StringBuilder result = new StringBuilder();
        boolean first = true;

        for (Map.Entry<String, Object> entry : values.valueSet())
        {
            if (first)
                first = false;
            else
                result.append("&");

            result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
            result.append("=");
            result.append(URLEncoder.encode(String.valueOf(entry.getValue()), "UTF-8"));
        }

        Log.i("Result",result.toString() +" "+ String.valueOf(response));

        return result.toString();
    }
}

我不知道我犯了什么错误。我得到了以下响应

name=ABC&email=abc%40xyz.com&password=123 0

空格后面的“0”是http响应代码返回的响应代码。当我在浏览器中尝试我的URL时，它是正确的。我不知道我犯了什么错误；是我的服务器出了问题还是我的代码有误，因为我不认为我的代码有任何交互处理。

我是Android开发的初学者，尝试了很多次和不同的代码，但是一直出现错误。

请帮忙！提前感谢。

- Swr7der

在 finally 语句中获取响应后，请尝试关闭写入器。 - Saeed Jassani

将其设置在 response = conn.getResponseCode() 和 conn.connect() 下面，但是仍然得到相同的响应，我已经删除了它，但是仍然得到相同的响应。 - Swr7der

我已经添加了我的代码作为参考...请检查并告诉我是否有帮助。 - Saeed Jassani

1个回答

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- Saeed Jassani · Accepted Answer

尝试这样做： ```html

像这样尝试：

```

try {
    url = new URL(params[0]);
    httpURLConnection = (HttpURLConnection) url.openConnection();
    httpURLConnection.setDoInput(true);
    httpURLConnection.setDoOutput(true);
    httpURLConnection.setRequestMethod("POST");



    outputStream = httpURLConnection.getOutputStream();

    bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream));
    bufferedWriter.write(myValues);
    bufferedWriter.flush();

    int statusCode = httpURLConnection.getResponseCode();
    Log.d(Constants.LOG_TAG, " The status code is " + statusCode);

    if (statusCode == 200) {
        inputStream = new BufferedInputStream(httpURLConnection.getInputStream());
        response = convertInputStreamToString(inputStream);
        Log.d(Constants.LOG_TAG, "The response is " + response);

        JSONObject jsonObject = new JSONObject(response);

return true;

    } else {
        return false;
    }

} catch (Exception e) {

    e.printStackTrace();
} finally {
    try {
        if (inputStream != null) {
            inputStream.close();
        }
        if (outputStream != null) {
            outputStream.close();
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
}