我可以做到这一点:
我该如何做相反的事情?
filter(lambda x: x.key1 in ["aa", "bb", "cc"], [{key1: ..., key2: ...}, {key1: ...}])
我该如何做相反的事情?
dict_items = [{key1: ..., key2: ...}, {key1: ...}]
filter(lambda x: x in ???dict_items.key1???, ["aa", "bb", "cc"])
x.key1
会给你一个属性错误。你能否在问题中添加一个示例输入和期望的输出?或者展示你代码的输出。 - Mazdak