分而治之
您试图使用一个简单的表达式解析过多的内容。这样做不会很好地工作。在这种情况下,最好的方法是将问题分解成较小的问题,并分别解决每个问题。然后,我们可以稍后将所有内容合并为一个模式。
让我们为您想要提取的数据编写一些模式。
Season/episode:
S\d+(?:E\d+(?:\s*\p{Pd}\s*E\d+)?)?
I used \p{Pd}
instead of -
to accommodate for any dash type.
Date:
\d{4}\.\d{1,2}\.\d{1,2}
Or...
(?i:January|February|March|April|May|June|July|August|September|October|November|December)
\s*\d{1,2},\s*\d{4}
Write a simple pattern for extra info:
.*?
(yeah, that's pretty generic)
We can also detect the show format like this:
\[.*?\]
You can add additional parts as required.
现在,我们可以将所有内容放进一个模式中,使用组名称来提取数据:
^\s*
(?<name>.*?)
(?<info> \s+ (?:
(?<episode>S\d+(?:E\d+(?:\s*\p{Pd}\s*E\d+)?)?)
|
(?<date>\d{4}\.\d{1,2}\.\d{1,2})
|
\(?(?<date>(?i:January|February|March|April|May|June|July|August|September|October|November|December)\s*\d{1,2},\s*\d{4})\)?
|
\[(?<format>.*?)\]
|
(?<extra>(?(info)|(?!)).*?)
))*
\s*$
只需要忽略 info
组 (它被用于在 extra
中的条件语句上,这样 extra
不会消耗应该属于展示名称的部分)。并且你可以得到多个 extra
信息,所以只需将它们连接起来,每个部分之间加一个空格。
示例代码:
var inputData = new[]
{
"Boyster S01E13 – E14",
"Mysteries at the Museum S08E08",
"Mysteries at the National Parks S01E07 – E08",
"The Last Days Of… S01E06",
"Born Naughty? S01E02",
"Have I Got News For You S49E07",
"Ellen 2015.05.22 Joseph Gordon Levitt [REPOST]",
"The Soup 2015.05.22 [mp4]",
"Big Brother UK Live From The House (May 22, 2015)",
"Alaskan Bush People S02 Wild Times Special",
"500 Questions S01E03"
};
var re = new Regex(@"
^\s*
(?<name>.*?)
(?<info> \s+ (?:
(?<episode>S\d+(?:E\d+(?:\s*\p{Pd}\s*E\d+)?)?)
|
(?<date>\d{4}\.\d{1,2}\.\d{1,2})
|
\(?(?<date>(?i:January|February|March|April|May|June|July|August|September|October|November|December)\s*\d{1,2},\s*\d{4})\)?
|
\[(?<format>.*?)\]
|
(?<extra>(?(info)|(?!)).*?)
))*
\s*$
", RegexOptions.IgnorePatternWhitespace);
foreach (var input in inputData)
{
Console.WriteLine();
Console.WriteLine("--- {0} ---", input);
var match = re.Match(input);
if (!match.Success)
{
Console.WriteLine("FAIL");
continue;
}
foreach (var groupName in re.GetGroupNames())
{
if (groupName == "0" || groupName == "info")
continue;
var group = match.Groups[groupName];
if (!group.Success)
continue;
foreach (Capture capture in group.Captures)
Console.WriteLine("{0}: '{1}'", groupName, capture.Value);
}
}
这个的输出结果是...
--- Boyster S01E13 - E14 ---
name: 'Boyster'
episode: 'S01E13 - E14'
--- Mysteries at the Museum S08E08 ---
name: 'Mysteries at the Museum'
episode: 'S08E08'
--- Mysteries at the National Parks S01E07 - E08 ---
name: 'Mysteries at the National Parks'
episode: 'S01E07 - E08'
--- The Last Days Ofâ?¦ S01E06 ---
name: 'The Last Days Ofâ?¦'
episode: 'S01E06'
--- Born Naughty? S01E02 ---
name: 'Born Naughty?'
episode: 'S01E02'
--- Have I Got News For You S49E07 ---
name: 'Have I Got News For You'
episode: 'S49E07'
--- Ellen 2015.05.22 Joseph Gordon Levitt [REPOST] ---
name: 'Ellen'
date: '2015.05.22'
format: 'REPOST'
extra: 'Joseph'
extra: 'Gordon'
extra: 'Levitt'
--- The Soup 2015.05.22 [mp4] ---
name: 'The Soup'
date: '2015.05.22'
format: 'mp4'
--- Big Brother UK Live From The House (May 22, 2015) ---
name: 'Big Brother UK Live From The House'
date: 'May 22, 2015'
--- Alaskan Bush People S02 Wild Times Special ---
name: 'Alaskan Bush People'
episode: 'S02'
extra: 'Wild'
extra: 'Times'
extra: 'Special'
--- 500 Questions S01E03 ---
name: '500 Questions'
episode: 'S01E03'
@"(.*?)S?(\d{1,2})E?(\d{1,2})(.*)|(.*?)S?(\d{1,2})E?(\d{1,2})"
- karthik manchala.*
可以匹配零个字符..?? - karthik manchala