public static void main(String[] args) throws ParseException {
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String str3 = "1927-12-31 23:54:07";
String str4 = "1927-12-31 23:54:08";
Date sDt3 = sf.parse(str3);
Date sDt4 = sf.parse(str4);
long ld3 = sDt3.getTime() /1000;
long ld4 = sDt4.getTime() /1000;
System.out.println(ld4-ld3);
}
输出结果为:
353
为什么是
ld4-ld3
而不是1
(根据时间差应该是1秒),而是353
?如果我将日期更改为晚1秒:
String str3 = "1927-12-31 23:54:08";
String str4 = "1927-12-31 23:54:09";
那么ld4-ld3
将会是1
。
Java版本:
java version "1.6.0_22"
Java(TM) SE Runtime Environment (build 1.6.0_22-b04)
Dynamic Code Evolution Client VM (build 0.2-b02-internal, 19.0-b04-internal, mixed mode)
Timezone(`TimeZone.getDefault()`):
sun.util.calendar.ZoneInfo[id="Asia/Shanghai",
offset=28800000,dstSavings=0,
useDaylight=false,
transitions=19,
lastRule=null]
Locale(Locale.getDefault()): zh_CN