如何向 PowerShell 脚本传递多个字符串参数？

Question

我正在尝试进行字符串拼接/格式化，但它把所有参数都放到了第一个占位符中。

代码

function CreateAppPoolScript([string]$AppPoolName, [string]$AppPoolUser, [string]$AppPoolPass)
{
    # Command to create an IIS application pool
    $AppPoolScript = "cscript adsutil.vbs CREATE ""w3svc/AppPools/$AppPoolName"" IIsApplicationPool`n"
    $AppPoolScript += "cscript adsutil.vbs SET ""w3svc/AppPools/$AppPoolName/WamUserName"" ""$AppPoolUser""`n"
    $AppPoolScript += "cscript adsutil.vbs SET ""w3svc/AppPools/$AppPoolName/WamUserPass"" ""$AppPoolPass""`n"
    $AppPoolScript += "cscript adsutil.vbs SET ""w3svc/AppPools/$AppPoolName/AppPoolIdentityType"" 3"

    return $AppPoolScript
}
$s = CreateAppPoolScript("name", "user", "pass")
write-host $s

输出

cscript adsutil.vbs CREATE "w3svc/AppPools/name user pass" IIsApplicationPool
cscript adsutil.vbs SET "w3svc/AppPools/name user pass/WamUserName" ""
cscript adsutil.vbs SET "w3svc/AppPools/name user pass/WamUserPass" ""
cscript adsutil.vbs SET "w3svc/AppPools/name user pass/AppPoolIdentityType" 3

- BrianLy

Answer 1

去掉括号和逗号。

将函数调用改为：

$s = CreateAppPoolScript "name" "user" "pass"

提供：

cscript adsutil.vbs CREATE "w3svc/AppPools/name" IIsApplicationPool
cscript adsutil.vbs SET "w3svc/AppPools/name/WamUserName" "user"
cscript adsutil.vbs SET "w3svc/AppPools/name/WamUserPass" "pass"
cscript adsutil.vbs SET "w3svc/AppPools/name/AppPoolIdentityType" 3

- Paul Roub

Answer 2

顺便提一下，使用 PowerShell 的 here-string 可能会让你的函数更易读，因为你不需要重复使用所有的 " 符号。

function CreateAppPoolScript([string]$AppPoolName, [string]$AppPoolUser, [string]$AppPoolPass)
{
  # Command to create an IIS application pool
  return @"
cscript adsutil.vbs CREATE "w3svc/AppPools/$AppPoolName" IIsApplicationPool
cscript adsutil.vbs SET "w3svc/AppPools/$AppPoolName/WamUserName" "$AppPoolUser"
cscript adsutil.vbs SET "w3svc/AppPools/$AppPoolName/WamUserPass" "$AppPoolPass"
cscript adsutil.vbs SET "w3svc/AppPools/$AppPoolName/AppPoolIdentityType" 3
"@
}

- Emperor XLII

Answer 3

保罗是正确的。
在PowerShell中，函数参数不需要用括号括起来。 （方法参数仍然需要。）
你最初的调用只是将一个大数组传递给函数，而不是你想要的三个单独的参数。

- Steven Murawski