我大约有40个API,其基本的响应结构如下:
{
"lastAccessed": "2015-30-08:14:21:45T",
"createdOn": "2015-30-07:09:04:10T",
"lastModified": "2015-30-08:14:21:45T",
"isReadOnly": "false",
"usersAllowed" : ["Tim", "Matt", "Christine"];
"noOfEntries": 1,
"object": [
"ObjectA": {
//here object A has its own model
}
]
}
所以,我有一个基本的响应类,使用类型T的泛型,如下所示:
public class Response<T> {
@ApiModelProperty(value="Last time accessed")
private String lastAccessed;
@ApiModelProperty(value="Time when Created ")
private String createdOn;
private String lastModified;
@ApiModelProperty(value="Created on")
private boolean isReadOnly;
@ApiModelProperty(value="Users that has access to the object.")
private List<String> usersAllowed;
private int noOfEntries;
private T object;
//getters and setters
}
对于返回自己字段类型的Object对象的API A,我在控制器中将Response作为API响应返回:
public class A {
@ApiModelProperty(value="Name")
private String name;
@ApiModelProperty(value="OID")
private String id;
//getters and setters
}
在控制器中: Response data = new Response(); ResponseEntity response = new ResponseEntity<>(data, HttpStatus.OK);
在Swagger中是否有一种方式可以递归地指定响应对象的模型?例如,我可以使用注释@ApiOperation(response=Response.class),但这不会具有A的模型。