使用PHP Html5进行视频流传输

Question

使用PHP Html5进行视频流传输

4

我有视频放在网站上，希望能够使用Php和html5实现视频流播放。我尝试按照这个教程(http://codesamplez.com/programming/php-html5-video-streaming-tutorial) 使用php类创建流媒体视频。

<?php
/**
 * Description of VideoStream
 *
 * @author Rana
 * @link http://codesamplez.com/programming/php-html5-video-streaming-tutorial
 */
class VideoStream
{
    private $path = "";
    private $stream = "";
    private $buffer = 102400;
    private $start  = -1;
    private $end    = -1;
    private $size   = 0;
 
    function __construct($filePath) 
    {
        $this->path = $filePath;
    }
     
    /**
     * Open stream
     */
    private function open()
    {
        if (!($this->stream = fopen($this->path, 'rb'))) {
            die('Could not open stream for reading');
        }
         
    }
     
    /**
     * Set proper header to serve the video content
     */
    private function setHeader()
    {
        ob_get_clean();
        header("Content-Type: video/mp4");
        header("Cache-Control: max-age=2592000, public");
        header("Expires: ".gmdate('D, d M Y H:i:s', time()+2592000) . ' GMT');
        header("Last-Modified: ".gmdate('D, d M Y H:i:s', @filemtime($this->path)) . ' GMT' );
        $this->start = 0;
        $this->size  = filesize($this->path);
        $this->end   = $this->size - 1;
        header("Accept-Ranges: 0-".$this->end);
         
        if (isset($_SERVER['HTTP_RANGE'])) {
  
            $c_start = $this->start;
            $c_end = $this->end;
 
            list(, $range) = explode('=', $_SERVER['HTTP_RANGE'], 2);
            if (strpos($range, ',') !== false) {
                header('HTTP/1.1 416 Requested Range Not Satisfiable');
                header("Content-Range: bytes $this->start-$this->end/$this->size");
                exit;
            }
            if ($range == '-') {
                $c_start = $this->size - substr($range, 1);
            }else{
                $range = explode('-', $range);
                $c_start = $range[0];
                 
                $c_end = (isset($range[1]) && is_numeric($range[1])) ? $range[1] : $c_end;
            }
            $c_end = ($c_end > $this->end) ? $this->end : $c_end;
            if ($c_start > $c_end || $c_start > $this->size - 1 || $c_end >= $this->size) {
                header('HTTP/1.1 416 Requested Range Not Satisfiable');
                header("Content-Range: bytes $this->start-$this->end/$this->size");
                exit;
            }
            $this->start = $c_start;
            $this->end = $c_end;
            $length = $this->end - $this->start + 1;
            fseek($this->stream, $this->start);
            header('HTTP/1.1 206 Partial Content');
            header("Content-Length: ".$length);
            header("Content-Range: bytes $this->start-$this->end/".$this->size);
        }
        else
        {
            header("Content-Length: ".$this->size);
        }  
         
    }
    
    /**
     * close curretly opened stream
     */
    private function end()
    {
        fclose($this->stream);
        exit;
    }
     
    /**
     * perform the streaming of calculated range
     */
    private function stream()
    {
        $i = $this->start;
        set_time_limit(0);
        while(!feof($this->stream) && $i <= $this->end) {
            $bytesToRead = $this->buffer;
            if(($i+$bytesToRead) > $this->end) {
                $bytesToRead = $this->end - $i + 1;
            }
            $data = fread($this->stream, $bytesToRead);
            echo $data;
            flush();
            $i += $bytesToRead;
        }
    }
     
    /**
     * Start streaming video content
     */
    function start()
    {
        $this->open();
        $this->setHeader();
        $this->stream();
        $this->end();
    }
}

我有两个问题：

1 - 我想要通过播放器进行视频流，但视频占据了整个页面，如何将视频添加到我的HTML5播放器中。

2 - 当我制作一个HTTP视频链接（http://video.newsmed.fr/pdv/0616.mp4），它无法工作。

请帮助我解决这个问题，或者建议其他的PHP解决方案。

- lynx_fg

3个回答

1

所以这是我的HTML。

<a href="#" onclick="play_video(event,`<?PHP echo $video_url?>`)">
<video  style="height:100%;width:100%" controls autoplay >
                    <source src="" type="video/mp4" id='video_player'>   
                </video>

然后使用以下jQuery。

<script>
    var play_video;
    $(document).ready(function(){

        play_video=function(event,video_url){
            event.preventDefault();
            console.log("play video");
            $('#video_player').attr('src',`index.php?action=play_video&file_path=${video_url}`);
        };

    });
    </script>

这是您的index.php文件

<?php
include "../util/VideoStream.php";

$action = filter_input(INPUT_POST, 'action');
if ($action === NULL) {
    $action = filter_input(INPUT_GET, 'action');
    if ($action === NULL) {
        $action = 'play_video';
    }
} else {
    $action = trim(strtolower($action));
}

switch ($action) {

    case 'play_video':
        $file_path = filter_input(INPUT_GET, 'file_path');
        $stream = new VideoStream($file_path);
        $stream->start();
        exit;
}
?>

- oo7developer

0

在类的顶部插入：

$stream = new VideoStream("file.mp4 or www//file.mp4");
$stream->start();exit;

- TRC4

网页内容由stack overflow 提供, 点击上面的

可以查看英文原文，
原文链接

- Jacky Supit · Accepted Answer

我也试图向播放器流媒体，但视频占据了整个页面，如何使视频仅添加到我的html5播放器中。

你只是复制了HTML示例而没有改变任何内容吗？看看HTML5示例，你会发现有width="100%"，你可以将值更改为适合你的值。

2 - 当我制作一个http视频链接（http://video.newsmed.fr/pdv/0616.mp4）时，它不起作用

URL应该指向你的php代码，而不是视频文件路径。例如：yourdomain.com/dir/your-php-file.php?video=0616.mp4

尝试在你的问题中放置your-php-file.php代码，而不是videostream.php类。