我正在寻找一个Delphi函数,用于根据分隔符将输入字符串拆分为字符串数组。我在网上搜索了很多,但它们都有自己的问题,我无法让它们正常工作。
我只需要按':'来拆分一个字符串,例如:
"word:doc,txt,docx"
拆分后得到的结果是
['word', 'doc,txt,docx']
。我该如何做?
我编写了这个函数,它返回由特定分隔符分隔的字符串链表。这是纯粹的无模块Pascal语言。
Program split_f;
type
PTItem = ^TItem;
TItem = record
str : string;
next : PTItem;
end;
var
s : string;
strs : PTItem;
procedure split(str : string;delim : char;var list : PTItem);
var
i : integer;
buff : PTItem;
begin
new(list);
buff:= list;
buff^.str:='';
buff^.next:=nil;
for i:=1 to length(str) do begin
if (str[i] = delim) then begin
new(buff^.next);
buff:=buff^.next;
buff^.str := '';
buff^.next := nil;
end
else
buff^.str:= buff^.str+str[i];
end;
end;
procedure print(var list:PTItem);
var
buff : PTItem;
begin
buff := list;
while buff<>nil do begin
writeln(buff^.str);
buff:= buff^.next;
end;
end;
begin
s := 'Hi;how;are;you?';
split(s, ';', strs);
print(strs);
end.
interface
TArrayStr = Array Of string;
implementation
function SplitString(Text: String): TArrayStr;
var
intIdx: Integer;
intIdxOutput: Integer;
const
Delimiter = ';';
begin
intIdxOutput := 0;
SetLength(Result, 1);
Result[0] := '';
for intIdx := 1 to Length(Text) do
begin
if Text[intIdx] = Delimiter then
begin
intIdxOutput := intIdxOutput + 1;
SetLength(Result, Length(Result) + 1);
end
else
Result[intIdxOutput] := Result[intIdxOutput] + Text[intIdx];
end;
end;
var slF, slR: IJclStringList; ai: TList<integer>; s: string; i: integer;
action: procedure(const Name: string; Const Data: array of integer);
slF := TJclStringList.Create; slF.LoadFromFile('some.txt');
slR := TJclStringList.Create;
for s in slF do begin
slR.Split(s, ' ', true);
ai := TList<Integer>.Create;
try
for i := 1 to slR.Count - 1 do
ai.Add(StrToInt(slR[i]));
action(slR[0], ai.ToArray);
finally ai.Free; end;
end;
http://wiki.delphi-jedi.org/wiki/JCL_Help:IJclStringList.Split@string@string@Boolean
procedure splitString(delim: char; s: string; ListOfStrings: TStrings);
var temp: string;
i: integer;
begin
ListOfStrings.Clear;
for i:=1 to length(s) do
begin
if s[i] = delim then
begin
ListOfStrings.add(temp);
temp := '';
end
else
begin
temp := temp + s[i];
if i=length(s) then
ListOfStrings.add(temp);
end;
end;
ListOfStrings.add(temp);
end;
ListOfStrings.add(temp);
以添加最后一个项目。 - rnso关于NGLG答案https://dev59.com/vHE85IYBdhLWcg3wwWUb#8811242的基础,您可以使用以下函数:
type
OurArrayStr=array of string;
function SplitString(DelimeterChars:char;Str:string):OurArrayStr;
var
seg: TStringList;
i:integer;
ret:OurArrayStr;
begin
seg := TStringList.Create;
ExtractStrings([DelimeterChars],[], PChar(Str), seg);
for i:=0 to seg.Count-1 do
begin
SetLength(ret,length(ret)+1);
ret[length(ret)-1]:=seg.Strings[i];
end;
SplitString:=ret;
seg.Free;
end;
它适用于所有Delphi版本。
对于 Delphi 2010,您需要创建自己的拆分函数。
function Split(const Texto, Delimitador: string): TStringArray;
var
i: integer;
Len: integer;
PosStart: integer;
PosDel: integer;
TempText:string;
begin
i := 0;
SetLength(Result, 1);
Len := Length(Delimitador);
PosStart := 1;
PosDel := Pos(Delimitador, Texto);
TempText:= Texto;
while PosDel > 0 do
begin
Result[i] := Copy(TempText, PosStart, PosDel - PosStart);
PosStart := PosDel + Len;
TempText:=Copy(TempText, PosStart, Length(TempText));
PosDel := Pos(Delimitador, TempText);
PosStart := 1;
inc(i);
SetLength(Result, i + 1);
end;
Result[i] := Copy(TempText, PosStart, Length(TempText));
end;
你可以这样称呼它
type
TStringArray = array of string;
var Temp2:TStringArray;
Temp1="hello:world";
Temp2=Split(Temp1,':')
我最初对@Frank的答案表示赞赏,因为我需要一个适用于Delphi 6的解决方案,并且它似乎有效。然而,后来我发现该解决方案存在一个bug,即无论分隔符如何,它仍然会在#13#10处进行拆分。如果您不希望在源字符串中出现换行符,则可以完美地工作。
我编写了一个简单的解析器,只适用于单个字符的分隔符。注意:它将值放入TStrings中,而不是像请求者要求的那样放入数组中,但可以很容易地修改以适应数组。
以下是该过程:
procedure SplitString(const ASource: string; const ADelimiter: Char; AValues: TStrings);
var
i, lastDelimPos: Integer;
begin
AValues.Clear;
lastDelimPos := 0;
for i := 1 to Length(ASource) do
if ASource[i] = ADelimiter then
begin
if lastDelimPos = 0 then
AValues.Add(CopyRange(ASource, 1, i - 1))
else
AValues.Add(CopyRange(ASource, lastDelimPos + 1, i - 1));
lastDelimPos := i;
end;
if lastDelimPos = 0 then
AValues.Add(ASource)
else
AValues.Add(CopyRange(ASource, lastDelimPos + 1, MaxInt));
end;
function CopyRange(const s: string; const AIndexFrom, AIndexTo: Integer): string;
begin
Result := Copy(s, AIndexFrom, AIndexTo - AIndexFrom + 1);
end;
procedure AddTest(const ATestLine: string; const AExpectedResult: array of string);
var
expectedResult: TStringList;
i: Integer;
begin
expectedResult := TStringList.Create;
for i := 0 to Length(AExpectedResult) - 1 do
expectedResult.Add(AExpectedResult[i]);
testStrings.AddObject(ATestLine, expectedResult);
end;
//====================
AddTest('test', ['test']);
AddTest('', ['']);
AddTest(',', ['', '']);
AddTest('line1' + #13#10 + ',line 2,line3, line 4', ['line1' + #13#10, 'line 2', 'line3', ' line 4']);
AddTest('line1' + #13#10 + 'd,line 2,line3, line 4', ['line1' + #13#10 + 'd', 'line 2', 'line3', ' line 4']);
AddTest('line1,line 2,line3, line 4', ['line1', 'line 2', 'line3', ' line 4']);
AddTest('test, ', ['test', ' ']);
AddTest('test,', ['test', '']);
AddTest('test1,test2 ', ['test1', 'test2 ']);
AddTest('test1,test2', ['test1', 'test2']);
AddTest('test1,test2, ', ['test1', 'test2', ' ']);
AddTest('test1,test2,', ['test1', 'test2', '']);
//====================
testFailed := False;
for i := 0 to testStrings.Count - 1 do
begin
SplitString2(testStrings[i], ',', f);
log('Test ID=%d', [i]);
log(' Test String="%s"', [testStrings[i]]);
log(' Item count=%d', [f.Count]);
testResult := TStringList(TestStrings.Objects[i]);
if testResult.Count <> f.Count then
begin
Log('!!');
Log('!! Count mismatch. Got=%d, Expected=%d', [f.Count, testResult.Count]);
Log('!!');
testFailed := True;
end;
for j := 0 to f.Count - 1 do
begin
log(' Item %d="%s" (len=%d)', [j, f[j], Length(f[j])]);
if testResult[j] <> f[j] then
begin
Log('!!');
Log('!! Text mismatch. Got="%s", Expected="%s"', [f[j], testResult[j]]);
Log('!!');
testFailed := True;
end;
end;
end;
编辑:CopyRange() 函数的代码丢失,现已添加。我的错。
procedure SplitCSV(S:STRING;out SL:TStringList);
var c,commatext:string;
a,b,up:integer;
begin
c:=s.Replace(' ','<SPACE>'); //curate spaces
//first ocurrence of "
a:=pos('"',c);
b:=pos('"',c,a+1);
if (a>0) and (b>0) then
begin
commatext:=commatext+copy(c,0,a-1);
commatext:=commatext+copy(c,a,b-a+1).Replace(',','<COMMA>'); //curate commas
up:=b+1;
end
else
commatext:=c;
//while continue discovering "
while (a>0) and (b>0) do
begin
a:=Pos('"',c,b+1);
b:=pos('"',c,a+1);
if (a>0) and (b>0) then
begin
commatext:=commatext+copy(c,up,a-up);
commatext:=commatext+copy(c,a,b-a+1).Replace(',','<COMMA>'); //curate commas
up:=b+1;
end;
end;
//last piece of text end
if up<c.Length then
commatext:=commatext+copy(c,up,c.Length-up+1);
//split text using CommaText
sl.CommaText:=commatext;
sl.Text:=sl.Text.Replace('<COMMA>',','); //curate commas
sl.Text:=sl.Text.Replace('<SPACE>',' '); //curate spaces
end;
*
//Basic functionality of a TStringList solves this:
uses Classes //TStringList
,types //TStringDynArray
,SysUtils //StringReplace()
;
....
//--------------------------------------------------------------------------
function _SplitString(const s:string; const delimiter:Char):TStringDynArray;
var sl:TStringList;
i:integer;
begin
sl:=TStringList.Create;
//separete delimited items by sLineBreak;TStringlist will do the job:
sl.Text:=StringReplace(s,delimiter,sLineBreak,[rfReplaceAll]);
//return the splitted string as an array:
setlength(Result,sl.count);
for i:=0 to sl.Count-1
do Result[i]:=sl[i];
sl.Free;
end;
//To split a FileName (last item will be the pure filename itselfs):
function _SplitPath(const fn:TFileName):TStringDynArray;
begin
result:=_SplitString(fn,'\');
end;
*
interface
uses
Classes;
type
TStringArray = array of string;
TUtilStr = class
class function Split(const AValue: string; const ADelimiter: Char = ';'; const AQuoteChar: Char = '"'): TStringArray; static;
end;
implementation
{ TUtilStr }
class function TUtilStr.Split(const AValue: string; const ADelimiter: Char; const AQuoteChar: Char): TStringArray;
var
LSplited: TStringList;
LText: string;
LIndex: Integer;
begin
LSplited := TStringList.Create;
try
LSplited.StrictDelimiter := True;
LSplited.Delimiter := ADelimiter;
LSplited.QuoteChar := AQuoteChar;
LSplited.DelimitedText := AValue;
SetLength(Result, LSplited.Count);
for LIndex := 0 to LSplited.Count - 1 do
begin
Result[LIndex] := LSplited[LIndex];
end;
finally
LSplited.Free;
end;
end;
end.