使用Spring JUnit测试时,带有两个Hibernate事务。

3

我有一个Spring JUnit测试,包含两个连续的事务,这些事务被传播为REQUIRES_NEW:

public class ContractServiceTest extends AbstractIntegrationTest {

@Autowired
private PersistenceManagerHibernate persistenceManagerHibernate;

@Autowired
private ContractService contractService;

@Autowired
private EntityChangeService entityChangeService;

@Resource
private AddServiceService addService;

@Autowired
private ReferenceBookService refService;

@Autowired
private PropertyService propertyService;

@Autowired
private HibernateTransactionManager transactionManager;

@Test
public void testContractDeletes() {
    Long contractId = 1L;
    final Contract contract = createTestDetachedContract(contractId, PropertyServiceTest.createManaged(propertyService, refService), refService);
    ensureContractCreated(contract);
    deleteTransactional(contract);
    Assert.assertEquals(1, entityChangeService.findByPaginationOrderByUpdateDate(Contract.class.getName(), contract.getId().toString(), null, 0, 30).size());
}

@Test
@Ignore
public void testContractCreates() {
    Long contractId = 1L;
    final Contract contract = createTestDetachedContract(contractId, PropertyServiceTest.createManaged(propertyService, refService), refService);
    ensureContractDeleted(contract);
    createContractTransactional(contract);
    Assert.assertEquals(1, entityChangeService.findByPaginationOrderByUpdateDate(Contract.class.getName(), contract.getId().toString(), null, 0, 30).size());
}

private void ensureContractCreated(Contract contract) {
    if (persistenceManagerHibernate.isCreated(Contract.class, contract.getId())) {          
        return;
    }
    createContractTransactional(contract);
}

private void deleteTransactional(final Contract contract) {
    TransactionTemplate transactionTemplate = new TransactionTemplate(transactionManager);
    transactionTemplate.setPropagationBehavior(Propagation.REQUIRES_NEW.value());
    transactionTemplate.execute(new TransactionCallback() {
        public Object doInTransaction(TransactionStatus status) {
            try {
                contractService.delete(contract);
            } catch (Exception e) {
                toString();
            }
            return null;
        }
    });
}

private void createContractTransactional(final Contract contract) {
    TransactionTemplate transactionTemplate2 = new TransactionTemplate(transactionManager);
    transactionTemplate2.setPropagationBehavior(Propagation.REQUIRES_NEW.value());
    transactionTemplate2.execute(new TransactionCallback() {
        public Object doInTransaction(TransactionStatus status) {
            contractService.create(contract);
            return null;
        }
    });
}

private void ensureContractDeleted(final Contract contract) {
    if (!persistenceManagerHibernate.isCreated(Contract.class, contract.getId())) {
        return;
    }
    deleteTransactional(contract);
}

public static Contract createTestDetachedContract(Long contractId, Property property, ReferenceBookService refService) {
    Contract contract1 = new Contract();
    contract1.setId(contractId);
    contract1.setName("test name");
    contract1.setProperty(property);
    contract1.setNumber("10");
    contract1.setType(refService.get(ContractType.class, 1L));
    contract1.setStatus(refService.get(ContractStatus.class, 1L));
    contract1.setCreated(new Date());
    contract1.setCurrencyRate(new BigDecimal(10));
    contract1.setInitialSum(new BigDecimal(10));
    contract1.setSum(new BigDecimal(10));
    return contract1;
}
}

测试在提交插入SQL语句的事务时冻结,插入语句如下:

 private void createContractTransactional(final Contract contract) {
    TransactionTemplate transactionTemplate2 = new TransactionTemplate(transactionManager);
    transactionTemplate2.setPropagationBehavior(Propagation.REQUIRES_NEW.value());
    transactionTemplate2.execute(new TransactionCallback() {
        public Object doInTransaction(TransactionStatus status) {
            contractService.create(contract);
            return null;
        }
    });
}

为什么会发生这种情况(调试器在没有提供源代码的情况下停留在某些Oracle代码处),以及如何正确编写具有两个连续事务的Spring JUnit测试?
1个回答

0

看起来测试在你的数据库的Contract表上创建了死锁。这主要原因可能是使用了PROPAGATION_REQUIRES_NEW传播级别,详见this question。其中重要的一部分是:

PROPAGATION_REQUIRES_NEW为给定范围启动一个新的、独立的“内部”事务。此事务将与外层事务完全独立地提交或回滚,具有自己的隔离范围、自己的锁集等。外部事务将在内部事务开始时被暂停,并在内部事务完成后恢复。

createContractTransactional方法试图插入Contract表,但测试中较早的某些内容必须持有该表的锁,我猜测是对的调用。无论原因是什么,你有两个相互独立的事务正在锁定同一个表,即发生了死锁。

尝试将测试中的事务传播级别设置为REQUIRED,这是默认设置。如果没有事务,则会创建一个新事务,否则将使用当前事务。这应该使您的测试在单个事务中执行,因此您不应该遇到死锁。一旦这样做了,您可能希望阅读spring documentation有关其传播级别的内容,以确保REQUIRED是您所需的正确级别。

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