我有一个字典想要格式化成表格:
band3 = \
{'channel1': [10564, 2112, 1922],
'channel10': [10787, 2157, 1967],
'channel11': [10812, 2162, 1972],
'channel12': [10837, 2167, 1977],
'channel2': [10589, 2117, 1927],
'channel3': [10612, 2122, 1932],
'channel4': [10637, 2127, 1937],
'channel5': [10662, 2132, 1942],
'channel6': [10687, 2137, 1947],
'channel7': [10712, 2142, 1952],
'channel8': [10737, 2147, 1957],
'channel9': [10762, 2152, 1962]}
我是这样做的:
table = [[], [], [], []]
# can't just sort the channel names because 'channel11' < 'channel2'
channel_numbers = []
for channel_name in band3.keys():
if channel_name.startswith('channel'):
channel_number = int(channel_name[7:])
channel_numbers.append(channel_number)
else:
raise ValueError("channel name doesn't follow pattern")
channel_numbers.sort()
for channel_number in channel_numbers:
channel_data = band2['channel%d' % channel_number]
column =[
'Channel %d' % channel_number,
str(channel_data[0]),
'%s/%s' % (channel_data[1], channel_data[2]),
str(channel_data[3])
]
cell_widths = map(len, column) #9 5 2 9
column_widths = max(cell_widths) # 9 or 10
for i in range(len(cell_widths)): #4
cell = column[i]
padded_cell = cell + ' '*(column_widths-len(cell))
table[i].append(padded_cell)
for line in table:
print(' '.join(line))
这将会得到:
Channel 1 Channel 2 Channel 3 Channel 4 Channel 5 Channel 6 Channel 7 Channel 8 Channel 9 Channel 10 Channel 11 Channel 12
10564 10589 10612 10637 10662 10687 10712 10737 10762 10787 10812 10837
2112/1922 2117/1927 2122/1932 2127/1937 2132/1942 2137/1947 2142/1952 2147/1957 2152/1962 2157/1967 2162/1972 2167/1977
20 0 0 26 32 0 26 0 0 0 0 15
现在我想给行命名:
Channel 1 Channel 2 Channel 3 Channel 4 Channel 5 Channel 6 Channel 7 Channel 8 Channel 9 Channel 10 Channel 11 Channel 12
UARFCN 10564 10589 10612 10637 10662 10687 10712 10737 10762 10787 10812 10837
DL/UL 2112/1922 2117/1927 2122/1932 2127/1937 2132/1942 2137/1947 2142/1952 2147/1957 2152/1962 2157/1967 2162/1972 2167/1977
RSSI 20 0 0 26 32 0 26 0 0 0 0 15
这很容易,我将打印循环更改为:
print " ",
print(' '.join(table[0]))
print "UARFCN",
print(' '.join(table[1]))
print "DL/UL ",
print(' '.join(table[2]))
print "RSSI ",
print(' '.join(table[3]))
然而我想知道一些更好的方法来打印这些列名。如上所述,我可以通过填充计算来详细说明,但我想知道是否有更简单、干净的方法。
编辑:格式化尝试:
print('{0:6s} {1}'.format("", ' '.join(table[0])))
print('{0:2s} {1}'.format("UARFCN", ' '.join(table[1])))
print('{0:6s} {1}'.format("DL/UL", ' '.join(table[2])))
print('{0:6s} {1}'.format("RSSI", ' '.join(table[3])))
编辑:另一种方法
print('{0} {1}'.format("".ljust(6), ' '.join(table[0])))
print('{0} {1}'.format("UARFCN".ljust(6), ' '.join(table[1])))
print('{0} {1}'.format("DL/UL".ljust(6), ' '.join(table[2])))
print('{0} {1}'.format("RSSI".ljust(6), ' '.join(table[3])))
有改进建议吗?
formatstr = '{0:6s} {1}'
然后使用它。 - Otaia