如何检查iPad是否为iPad Pro

Question

新的iPad Pro有不同的尺寸和分辨率。如果我根据屏幕宽度来检查，这样做是否正确？我还没有升级到Xcode 7.1，也没有设备，所以我还不能检查。这种检查方法可行吗？

if([UIScreen mainScreen].bounds.size.width>1024)
    {
        // iPad is an iPad Pro
    }

- Francis F

---

你忽略设备的方向。 - El Tomato

Answer 1

你可以使用这个

#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define SCREEN_WIDTH ([[UIScreen mainScreen] bounds].size.width)
#define SCREEN_HEIGHT ([[UIScreen mainScreen] bounds].size.height)
#define IS_IPAD_PRO_1366 (IS_IPAD && MAX(SCREEN_WIDTH,SCREEN_HEIGHT) == 1366.0)
#define IS_IPAD_PRO_1024 (IS_IPAD && MAX(SCREEN_WIDTH,SCREEN_HEIGHT) == 1024.0)

然后

 if (IS_IPAD_PRO_1366) {
    NSLog(@"It is ipad pro 1366");
  }

- Leo

---

iPad Pro 1024是什么？您是在暗示有2个型号吗？ - TahoeWolverine

我相信，最后一行应该是MIN而不是MAX。 - FreeNickname

Answer 2

+(BOOL) isIpad_1024
{

    if ([UIScreen mainScreen].bounds.size.height == 1024) {
        return  YES;
    }
    return NO;
}

+(BOOL) isIpadPro_1366
{

    if ([UIScreen mainScreen].bounds.size.height == 1366) {
        return  YES;
    }
    return NO;
}

- pankaj raghav

Answer 3

目前看来，这个宏似乎没有任何问题，已经能够胜任了。

#define IS_IPAD_PRO (MAX([[UIScreen mainScreen]bounds].size.width,[[UIScreen mainScreen] bounds].size.height) > 1024)

- Francis F

Answer 4

正如HAS在这里提到的，请在您的代码中添加以下扩展：

public extension UIDevice {
    var modelName: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 where value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }

        switch identifier {
        case "iPod5,1":                                 return "iPod Touch 5"
        case "iPod7,1":                                 return "iPod Touch 6"
        case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
        case "iPhone4,1":                               return "iPhone 4s"
        case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
        case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
        case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
        case "iPhone7,2":                               return "iPhone 6"
        case "iPhone7,1":                               return "iPhone 6 Plus"
        case "iPhone8,1":                               return "iPhone 6s"
        case "iPhone8,2":                               return "iPhone 6s Plus"
        case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
        case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
        case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
        case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
        case "iPad5,1", "iPad5,3", "iPad5,4":           return "iPad Air 2"
        case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
        case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
        case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
        case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
        case "iPad6,7", "iPad6,8":                      return "iPad Pro"
        case "i386", "x86_64":                          return "Simulator"
        default:                                        return identifier
        }
    }
}

并且用于检查。

if(UIDevice.currentDevice().modelName == "iPad Pro"){//Your code}

- Manuel

---

这段代码已经被多次发布，例如在https://dev59.com/g18e5IYBdhLWcg3wJnyl#26962452。如果您从其他来源复制代码，请添加原始链接以进行适当的归属。 - Martin R

Answer 5

SWIFT

这是一种使用 Swift 语言编写的标准答案。

let isIpadPro:Bool = max(UIScreen.main.bounds.size.width, UIScreen.main.bounds.size.height) > 1024

- Brandon A

Answer 6

这个宏在横屏和竖屏都可以工作：

#define IS_IPAD_PRO_12_INCH (([UIScreen mainScreen].bounds.size.width == 1366 && [UIScreen mainScreen].bounds.size.height == 1024) || ([UIScreen mainScreen].bounds.size.width == 1024 && [UIScreen mainScreen].bounds.size.height == 1366))

- Jason McClinsey

Answer 7

试试这个库：https://github.com/fahrulazmi/UIDeviceHardware

然后你的代码应该是：

NSString *platform = [UIDeviceHardware platformString];
if ([platform isEqualToString:@"iPad6,7"] || [platform isEqualToString:@"iPad6,8"]) {
     // iPad is an iPad Pro
}

或者使用这个更强大的库： https://github.com/InderKumarRathore/DeviceUtil

该解决方案无法在模拟器上运行。如果你想检查模拟器的设备类型，似乎只能检查屏幕尺寸。

- Harrison Xi

Answer 8

你可以使用这段代码：

#include <sys/types.h>
#include <sys/sysctl.h>

- (BOOL) isIpadPro{
    size_t size;
    sysctlbyname("hw.machine", NULL, &size, NULL, 0);
    char *machine = malloc(size);
    sysctlbyname("hw.machine", machine, &size, NULL, 0);
    NSString *platform = [NSString stringWithUTF8String:machine];
    free(machine);

    if ([platform isEqualToString:@"iPad6,8"])
        return YES;

    return NO;
}

- Jiri Zachar

Answer 9

我的完整设备检测集合。

#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_RETINA ([[UIScreen mainScreen] scale] >= 2.0)

#define SCREEN_WIDTH ([[UIScreen mainScreen] bounds].size.width)
#define SCREEN_HEIGHT ([[UIScreen mainScreen] bounds].size.height)
#define SCREEN_MAX_LENGTH (MAX(SCREEN_WIDTH, SCREEN_HEIGHT))
#define SCREEN_MIN_LENGTH (MIN(SCREEN_WIDTH, SCREEN_HEIGHT))

#define IS_IPHONE_4_OR_LESS (IS_IPHONE && SCREEN_MAX_LENGTH < 568.0)
#define IS_IPHONE_5 (IS_IPHONE && SCREEN_MAX_LENGTH == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && SCREEN_MAX_LENGTH == 667.0)
#define IS_IPHONE_6P (IS_IPHONE && SCREEN_MAX_LENGTH == 736.0)
#define IS_IPHONE_X (IS_IPHONE && SCREEN_MAX_LENGTH == 812.0)

#define IS_IPAD_PRO_97 (IS_IPAD && SCREEN_MAX_LENGTH == 1024.0)
#define IS_IPAD_PRO_105 (IS_IPAD && SCREEN_MAX_LENGTH == 1112.0)
#define IS_IPAD_PRO_129 (IS_IPAD && SCREEN_MAX_LENGTH == 1366.0)

- Dody Rachmat Wicaksono

---

你漏掉了 IS_IPAD。 - Ryan Wu

Answer 10

当我在Xcode 8的模拟器中进行测试时，这些解决方案都没有起作用。

诀窍是要查找“nativeBounds”大小高度，否则您将继续在模拟器中获得1024的高度。

#define iPadPro12 (UIDevice.currentDevice.userInterfaceIdiom == UIUserInterfaceIdiomPad && UIScreen.mainScreen.nativeBounds.size.height > 1024)

if (iPadPro12)
{
  //its ipad Pro 12.9 inch screen
}

- Sam B