Android O - 指纹手势回调不起作用

11

我正在使用启用了指纹手势的Pixel设备进行测试。我尝试使用FingerprintGestureController获取手势回调,但即使我从“设置”->“辅助功能”中为此应用程序启用辅助功能,也从未获得任何手势返回。isGestureDetectionAvailable()始终对我返回false。请问有人可以帮忙吗。

以下是代码:

my_gesture_service.xml

<accessibility-service xmlns:android="http://schemas.android.com/apk/res/android"
android:accessibilityFeedbackType="feedbackGeneric"
android:accessibilityFlags="flagDefault"
android:canRequestFingerprintGestures="true" />

AndroidManifest.xml

<uses-feature android:name="android.hardware.fingerprint"/>
    <uses-permission android:name="android.permission.USE_FINGERPRINT" />
    <uses-permission android:name="android.permission.BIND_ACCESSIBILITY_SERVICE"/>
<service
            android:name="android.gestures.MyService"
            android:label="@string/app_name"
            android:permission="android.permission.BIND_ACCESSIBILITY_SERVICE">
            <intent-filter>
                <action android:name="android.accessibilityservice.AccessibilityService" />
            </intent-filter>
            <meta-data
                android:name="android.accessibilityservice"
                android:resource="@xml/my_gesture_service" />
        </service>

MyService.java

public class MyService extends AccessibilityService {

    private static final String TAG = MyService.class.getSimpleName();

    @Override
    public void onAccessibilityEvent(AccessibilityEvent accessibilityEvent) {
        Log.d(TAG, "onAccessibilityEvent");
    }

    @Override
    public void onInterrupt() {
        Log.d(TAG, "onInterrupt");
    }

    @Override
    protected boolean onGesture(int gestureId) {
        Log.d(TAG, "onGesture " + gestureId);
        return super.onGesture(gestureId);
    }

    @Override
    protected boolean onKeyEvent(KeyEvent event) {
        Log.d(TAG, "onKeyEvent " + event.getKeyCode());
        return super.onKeyEvent(event);
    }

    @Override
    public void onDestroy() {
        Toast.makeText(getApplicationContext(), "onDestroy" , Toast.LENGTH_SHORT).show();
        super.onDestroy();
    }



    @Override
    protected void onServiceConnected() {
        super.onServiceConnected();
        Log.d(TAG, "onServiceConnected");

        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {

            FingerprintGestureController gestureController = getFingerprintGestureController();

            Toast.makeText(getApplicationContext(), "Is available: " + gestureController.isGestureDetectionAvailable(), Toast.LENGTH_LONG).show();
            Log.e(TAG, "Is available: " + gestureController.isGestureDetectionAvailable() );

            FingerprintGestureController.FingerprintGestureCallback callback = new
                    FingerprintGestureController.FingerprintGestureCallback() {
                        @Override
                        public void onGestureDetectionAvailabilityChanged(boolean available) {
                            super.onGestureDetectionAvailabilityChanged(available);
                            Toast.makeText(getApplicationContext(), "Gesture available change to: " + available, Toast.LENGTH_SHORT).show();
                            Log.d(TAG, "onGestureDetectionAvailabilityChanged " + available);
                        }

                        @Override
                        public void onGestureDetected(int gesture) {
                            super.onGestureDetected(gesture);
                            Toast.makeText(getApplicationContext(), "Gesture: " + gesture, Toast.LENGTH_SHORT).show();
                            Log.d(TAG, "onGestureDetected " + gesture);
                        }
                    };

            gestureController.registerFingerprintGestureCallback(callback, new Handler());
        }
    }

    @Override
    public boolean onUnbind(Intent intent) {
        Log.d(TAG, "onUnbind " );
        return super.onUnbind(intent);
    }


}
1个回答

12

找到答案了。我还需要在xml中加上这个标志。

android:accessibilityFlags="flagDefault|flagRequestFingerprintGestures"

1
嘿!即使做了这些事情,我的还是不工作!你能帮忙吗? - Aayushi
1
我也遇到了相同的问题...设置了一切,但isGestureDetectionAvailable()总是返回false。我找不到任何调试的方法,它似乎是一个黑盒子。 - Dane Powell
@DanePowell 你找到解决方案了吗? - Ashraf Alshahawy
@Aayushi,你找到解决方案了吗? - Ashraf Alshahawy

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